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3 years ago

What factors affect freezing-point depression of a solution? (select all that apply)

Chemistry

1 answer:

ANTONII [103]3 years ago

8 0

Answer:

A and F i think

Explanation:

Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all lower than that of the pure solvent and is directly proportional to the molality of the solute

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How many millimeters of 1.58 M HCl are needed to react completely with 23.2 g of NaHCO3

KonstantinChe [14]

So we need 0.276 moles of HCl to react. Your concentration is given in moles/liter so 0.276/1.58 = 0.174 liters needed or 174 milliliters

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3 years ago

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How is the water cycle realated to weather patterns and climate? Make sure to put 2 evidences

Setler79 [48]

When there’s water in a department such as a lake, pound or/and ocean, the water tends to evaporated into the air and that’s how/when clouds are created. The same water from those locations are the same water that comes from the rain water, it’s a cycle that creates and takes water

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2 years ago

How many moles of carbon, hydrogen, and oxygen are present in a 100-g sample of ascorbic acid?

Y_Kistochka [10]

There are:

3.41 moles of C

4.54 moles of H

3.40 moles of O.

Why?

To solve the problem, the first thing that we need to do is to write the chemical formula of the ascorbic acid.

$C_{6}H_{8}O_{6}$

Now, we know that there are 100 grams of the compound, so, the masses of each element will represent the percent in the compound.

We have that:

$C_{6}=12.0107g*6=72.08g\\\\H_{8}=1.008g*8=8.064g\\\\O_{6}=15.999g*6=95.994g\\\\C_{6}H_{8}O_{6}=72.08g+8.064g+95.994g=176.138g$

To know the percent of each element, we need to to the following:

$C=\frac{72.08g}{176.138g}*100=0.409*100=40.92(percent)\\\\H=\frac{8.064g}{176.138g}*100=4.58(percent)\\\\O=\frac{95.994}{176.138g}*100=54.49(percent)$

So, we know that for the 100 grams of the compound, there are:

40.92 grams of C

4.58 grams of H

54.49 grams of O

We know the molecular masses of each element:

$C=12.0107\frac{g}{mol}\\\\H=1.008\frac{g}{mol}\\\\O=15.999\frac{g}{mol}{mol}$

Now, to calculate the number of moles of each element, we need to divide the mass of each element by the molecular mass of each element:

$C=\frac{40.92g}{12.010\frac{g}{mol}}=3.41mol\\\\H=\frac{4.58g}{1.008\frac{g}{mol}}=4.54mol\\\\O=\frac{54.49g}{15.999\frac{g}{mol}}=3.40mol$

Hence, we have that there are 3.41 moles of C, 4.54 moles of H, and 3.40 moles of O.

Have a nice day!

5 0

3 years ago

Nonliving things have cells. True False

Whitepunk [10]

The answer is false.

3 0

3 years ago

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Iron Choose one: A. is alloyed with carbon and chromium to make stainless steel. B. was the first of the common metals (iron, al

Lostsunrise [7]

Answer:

A. is alloyed with carbon and chromium to make stainless steel.

Explanation:

Steel is an alloy formed mainly of iron and carbon but some other metals like chromium are also added in little amounts.

Is steel, the percentage of iron and carbon together is about 90% and the rest metals fall in the 10% part.

Although the cost of steel is low, it has a very high tensile strength and that's why it is used in tools, ships, buildings, trains and in various types of infrastructures.

7 0

2 years ago