It is because the space between particles decreases but also looses energy at the same time.
Answer:
-255.4 kJ
Explanation:
The free energy of a reversible reaction can be calculated by:
ΔG = (ΔG° + RTlnQ)*n
Where R is the gas constant (8.314x10⁻³ kJ/mol.K), T is the temperature in K, n is the number of moles of the products (n =1), and Q is the reaction quotient, which is calculated based on the multiplication of partial pressures by the partial pressure of the products elevated by their coefficient divide by the multiplication of the partial pressure of the reactants elevated by their coefficients.
C₂H₂(g) + 2H₂(g) ⇄ C₂H₆(g)
Q = pC₂H₆/[pC₂H₂ * (pH₂)²]
Q = 0.261/[8.58*(3.06)²]
Q = 3.2487x10⁻³
ΔG = -241.2 + 8.314x10⁻³x298*ln(3.2487x10⁻³)
ΔG = -255.4 kJ
For 5.43 g/mL and 5.44 g/mL = 0.01 the least diff and most precise.
First of all, precision is determined by the difference in the two obtained values. If the difference between the two values obtained is less, then precision is more. If the difference between the two values obtained is more, then precision is less.
For 5.43 g/mL and 5.44 g/mL , we can see that the difference between these two data is 0.01
For 7.98 g/mL and 7.91 g/mL , we can see that the difference between these two data is 0.07
For 7.65 g/mL and 7.64 g/mL , we can see that the difference between these two data is 0.01
For 7.06 g/mL and 7.03 g/mL , we can see that the difference between these two data is 0.03
As we can see that, the most difference between the data is 0.07 between 7.65 g/mL and 7.64 g/mL and thus, they are least precise.
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Explanation:
Air borne pollutants are usually very light particles that are usually carried in the air in the atmosphere. Some of these pollutants can be carried far away and some are found close to their sources.
Some of the factors are:
- Wind pressure: if wind pressure is low, pollutants will not be carried far away. In this situation, the particles will be blown and carried over a short distance from their sources. When wind pressure is very high, pollutants will be carried extensively into farther areas.
- Pollutants can be trapped in snow. In a snowy area, when pollutants reach sky high and enters condensed water in the atmosphere, they can become super cooled into ice and fall back within the same area where they are formed.
- Rain water can also cause pollutants to be dispersed within a short area. Pollutants can mix with rain water and carrier back to the area where they were originally formed.
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Answer:
24 hours
Explanation:
The computation is shown below:
The needed mole of 
is
= 5 ÷22.4 = n
Also 1 mole of required four electric charge
Now the charge needed is
= n × 4 × 96,500 C
= 4 × 96,500 × 5 c ÷ 22.4
= 86160.714 C
Now
q = i t
t = q ÷ i
= 86160.714 C ÷ 0.995
= 86593.7 seconds
= 24 hours
Hence, the correct option is A.
