Answer: The values for Ka and Kb for the species in solution must be known before a prediction can be made
Explanation:
1. If Ka is greater than Kb, the salt solution is acidic
2. If Ka is lesser than Kb, the salt solution is basic
3. If Ka is equal to Kb, the salt solution is acidic
Answer:
2Al(s) +3Ni²⁺(aq) ⟶ 2Al³⁺(aq) + 3Ni(s)
Explanation:
The unbalanced equation is
Al(s) + Ni²⁺(aq) ⟶ Ni(s) + Al³⁺(aq)
(i) Half-reactions
Al(s) ⟶ Al³⁺(aq) + 3e⁻
Ni²⁺(aq) + 2e⁻ ⟶ Ni(s)
(ii) Balance charges
2 × [Al(s) ⟶ Al³⁺(aq) + 3e⁻]
3 × [Ni²⁺(aq) + 2e⁻ ⟶ Ni(s)]
gives
2Al(s) ⟶ 2Al³⁺(aq) + 6e⁻
3Ni²⁺(aq) + 6e⁻ ⟶ 3Ni(s)
(iii) Add equations
2Al(s) ⟶ 2Al³⁺(aq) + 6e⁻
<u>3Ni²⁺(aq) + 6e⁻ ⟶ 3Ni(s) </u>
2Al(s) +3Ni²⁺(aq) + <em>6e</em>⁻ ⟶ 2Al³⁺(aq) + 3Ni(s) + <em>6e⁻
</em>
Simplify (cancel electrons)
2Al(s) +3Ni²⁺(aq) ⟶ 2Al³⁺(aq) + 3Ni(s)
1 grams F2 to mol = 0.02632 mol
10 grams F2 to mol = 0.26318 mol
20 grams F2 to mol = 0.52636 mol
30 grams F2 to mol = 0.78954 mol
40 grams F2 to mol = 1.05272 mol
50 grams F2 to mol = 1.3159 mol
100 grams F2 to mol = 2.6318 mol
200 grams F2 to mol = 5.2636 mol
