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Darya [45]
3 years ago
13

A simple machine produces 25 joules of output work for every 50 joules of input work . What is the efficiency of this machine ?

Snow work too plz
Chemistry
1 answer:
nataly862011 [7]3 years ago
8 0
2:1, output is half the input
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WARRIOR [948]

Answer:

11.009306 or 11.009

Explanation:

boron 11 has atomic mass of 11.009306

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Lionel places red blood cells in a beaker of pure water, and then he observes their
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Answer:

The red blood cells will burst

Explanation:

When the red blood cells are placed in pure water, they will gain water by osmosis, swell and finally burst due to their weak cell membranes. This process is referred to as hemolysis.

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According to Le Chatelier’s principle, what happens when the concentration of reactants is doubled in a chemical reaction that w
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If more reactant is added, the equation will shift to the right in order to make more product (which will increase the products)
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3 years ago
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Which of the following has potential energy but no kinetic energy? Longitudinal sound waves An arrow shot from a bow A compresse
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Answer:

A compressed spring

Explanation:

A compressed spring has potential energy only and no kinetic energy.

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In this equation there is no velocity so there is no kinetic energy.

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A chemist must prepare 300.0mL of nitric acid solution with a pH of 0.70 at 25°C. He will do this in three steps: Fill a 300.0mL
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<u>Answer:</u> The volume of concentrated solution required is 9.95 mL

<u>Explanation:</u>

To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

pH = 0.70

Putting values in above equation, we get:

0.70=-\log[H^+]

[H^+]=10^{-0.70}=0.199M

1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions.

Molarity of nitric acid = 0.199 M

To calculate the volume of the concentrated solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated nitric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted nitric acid solution

We are given:

M_1=7.0M\\V_1=?mL\\M_2=0.199M\\V_2=350mL

Putting values in above equation, we get:

7.0\times V_1=0.199\times 350.0\\\\V_1=\frac{0.199\times 350}{7.0}=9.95mL

Hence, the volume of concentrated solution required is 9.95 mL

6 0
3 years ago
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