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1 year ago

seven less than the sum of p and t is as much as nine times a number y subtracted from 85 is seven times the sum of four and y

Mathematics

1 answer:

natita [175]1 year ago

5 0

7-(p+t) = 9(85-n) = 7(4+y)

Algebra is a kind of mathematics that includes symbols and the arithmetic operations across these symbols. These symbols do not have any fixed values and are called variables.

An algebra expression contain coefficient variable and a constant

We apply various methods to solve those question

An algebra expression is also called an equation

let the number be x

Seven less than the of p and t

= 7-(p+t)…….(1)

Nine times a number y subtracted from 85

= 9(85-n)…..(2)

Seven times the sum of four and y

= 7(4+y)……(3)

Combining equations (1), (2) and (3) according to the question :

7-(p+t) = 9(85-n) = 7(4+y)

Learn about algebra here :

brainly.com/question/2972832

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1. (5pt) In a recent New York City marathon, 25,221 men finished and 253 dropped out. Also,

gladu [14]

Answer:

(a) Explained below.

(b) The 99% confidence interval for the difference between proportions is (-0.00094, 0.00494).

Step-by-step explanation:

The information provided is:

n (Men who finished the marathon) = 25,221

n (Women who finished the marathon) = 12,883

Compute the proportion of men and women who finished the marathon as follows:

$\hat p_{1}=\frac{25221}{25221 +253}=0.99\\\\\hat p_{2}=\frac{12883 }{12883+163}=0.988$

The combined proportion is:

$\hat P=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}\\\\=\frac{25221+12883}{38520}\\\\=0.989$

(a)

The hypothesis is:

H₀: The rate of those who finish the marathon is the same for men and women, i.e. p₁ - p₂ = 0.

Hₐ: The rate of those who finish the marathon is not same for men and women, i.e. p₁ - p₂ ≠ 0.

Compute the test statistic as follows:

$Z=\frac{\hat p_{1}-\hat p_{2}}{\sqrt{\hat P(1-\hat P)\cdot [\frac{1}{n_{1}}+\frac{1}{n_{2}}]}}$

$=\frac{0.99-0.988}{\sqrt{0.989(1-0.989)\times[\frac{1}{25474}+\frac{1}{13046}]}}\\\\=1.78$

Compute the p-value as follows:

$p-value=2\times P(Z>1.78)\\\\=2\times 0.03754\\\\=0.07508\\\\\approx 0.075$

The p-value of the test is more than the significance level. The null hypothesis was failed to be rejected.

Thus, concluding that the rate of those who finish is the same for men and women.

(b)

Compute the 99% confidence interval for the difference between proportions as follows:

The critical value of z for 99% confidence level is 2.58.

$CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\cdot\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}$

$=(0.99-0.988)\pm 2.58\times\sqrt{\frac{0.99(1-0.99)}{25474}+\frac{0.988(1-0.988)}{13046}}\\\\=0.002\pm 0.00294\\\\=(-0.00094, 0.00494)\\\\$

Thu, the 99% confidence interval for the difference between proportions is (-0.00094, 0.00494).

6 0

3 years ago

Solveeee please :( 6/25 × 3/4 ÷ 16/5

yarga [219]

Answer:

6/25 x 3/4 = 18/100 % 16/5 = 18/100 x 5/16 = 90/1600 or 0.05625

Can also be simplified to 9/160

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2 years ago

Below is a table for f(x) = 3x + 1. Using the table, determine the value of x when f(x) = 13

Elena L [17]

3x+1=13
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2 years ago

Consider the logarithms base 5. For each logarithmic expression below, either calculate the value of the expression or explain w

Tom [10]

Answer:

log₅(3125) = 5

Step-by-step explanation:

Given:

log₅(3125)

Now,

using the property of log function that

logₐ(b) = $\frac{\log(b)}{\log(a)}$

thus,

Therefore, applying the above property, we get

⇒ $\frac{\log(3125)}{\log(5)}$ (here log = log base 10)

now,

3125 = 5⁵

thus,

⇒ $\frac{\log(5^5)}{\log(5)}$

Now,

we know from the properties of log function that

log(aᵇ) = b × log(a)

therefore applying the above property we get

⇒ $\frac{5\log(5)}{\log(5)}$

⇒ 5

Hence,

log₅(3125) = 5

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2 years ago

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mel-nik [20]

Um idk if its right but i think
s would be -3,6
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3 years ago