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3 years ago

10

An Olympic -size swimming pool in the shape of a rectangular solid has a volume of 3150 cubic meters,, a length of 70 meters,, a

nd a width of 35 meters.What is the depth of the pool????

1 answer:

Lyrx [107]3 years ago

5 0

Volume=length*width*depth.
=>
3150=70*35*D
=>
D=3150/(70*35)
=9/7 m
=1.286m

(hope athletes don't dive in this pool)

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$\boxed{\sf distance \: between \: the \: objects \: \: is \: 2.5 \: cm}$

Step-by-step explanation:

According to universal law of gravitation every object in the universe attracts every other particles that surrounds it with a force which is inversely proportional to the square of their distance of separation & directly proportional to

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$A = G \cdot \frac{m_1.m_2}{ {d}^{2} }$

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<em>Given:</em>

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<em>To find:</em>

Distance of separation when the force of attraction is 8 units d2 = ?

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Substituting the given values in above at each point,

$A_1 = G \cdot \frac{m_1.m_2}{ {d_1}^{2} } \\ 2 = G \cdot \frac{m_1.m_2}{ {5}^{2} } \\ \sf similarly \: at \: second \: point \: of \: attraction \\ A_2 = G \cdot \frac{m_1.m_2}{ {d_2}^{2} } \\ 8 = G \cdot \frac{m_1.m_2}{ {d_2}^{2} } \\ \sf \: \: dividing \: both \: of \: the \: equation \\ \frac{2}{8} = \frac{G \cdot \frac{m_1.m_2}{ {5}^{2} }}{G \cdot \frac{m_1.m_2}{ {d_2}^{2} } } \\ \sf \: G \: m_1 and \: m_2 \: are \: \: constant \: hence \\ \sf they \: can \: be \: cancelled \: out \\ \frac{2}{8} = \frac{ \frac{1}{ {5}^{2} } }{ \frac{1}{ {d_2}^{2} } } \\ \sf rearranging \: above \: equation \\ \frac{1}{4} = \frac{{d_2}^{2} }{ {5}^{2} } \\ {d_2}^{2} = \frac{ {5}^{2} }{4 } \\ {d_2}^{2} = \frac{25}{4} \\ {d_2}^{2} = 6.25 \\ \sqrt{{d_2}^{2} } = \sqrt{6.25} \\ \boxed{ \sf{d_2} = 2.5 \: cm}$

<em>Answer:</em><em> </em><em>the distance between the two </em><em>objects </em><em>is </em><em>2</em><em>.</em><em>5</em><em> </em><em>cm</em><em>, if the attraction between them is 8 </em><em>units.</em>

<em><u>Learn more about universal law of gravitation here brainly.com/question/27244479</u></em>

<em>Thanks </em><em>for </em><em>joining </em><em>brainly </em><em>community</em><em>!</em>

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