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victus00 [196]
2 years ago
15

A 25-ohm resistor at steady state draws a current of 10.8 amperes. its temperature is 310 k; the temperature of the surroundings

is 300 k. what is the total rate of entropy generation ?
Physics
1 answer:
MA_775_DIABLO [31]2 years ago
3 0

The total rate of entropy generation is 0.268 J/K.

Entropy, the degree of a gadget's thermal electricity consistent with unit temperature that is unavailable for doing useful paintings. due to the fact work is acquired from ordered molecular motion, the quantity of entropy is likewise a measure of the molecular sickness, or randomness, of a machine.

Resistance of resistor R = 25 ohm

the total rate of entropy generation ?

Current flowing through resistor I = 10 A

Heat generation due to resistance , Q = I2R = 100*25 = 2500 J

Resistor temperature T = 310 K

Surrounding temperature Ts = 300 K

Entropy change for Resistor, heat lost due to the resistance to the surrounding then Q = -ve

(ΔS)syst = - Q/T = - 2500 J/310K = - 8.064 J/K

Entropy change for the system: here heat gain from the resistor, Q = +ve

(ΔS)surr = +Q/Ts = 2500J/300K = 8.333 J/K

Total Entropy generation :

(ΔS)tot = (ΔS)syst + (ΔS) Surr = -8.064 + 8.333 = 0.268 J/K

Learn more about entropy here:- brainly.com/question/6364271

#SPJ4

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is it possible for the gravitational force between two 50-kg objects to be less than the gravitational force between a 59-kg obj
Eva8 [605]

OF COURSE !  

The gravitational force between two objects doesn't ONLY depend on the product of their masses.  It also depends on the distance between them.

I'm not even going to work out the numbers for my example.  I'm just going to state without proof that at the top of the 2nd frame, the gravitational force between you and your bowling ball is greater than the gravitational force between you and the whole darn Andromeda galaxy !  My reasoning is based on the fact that your bowling ball is maybe 1 foot from your center of mass, whereas the Andromeda galaxy is more like 2.5 million light years from it.  That right there is going to give your bowling ball a big advantage when it comes to gravity !

5 0
3 years ago
Consider a particle with unit charge q, and mass m, in a constant magnetic field B directed along the positive z–axis. The parti
max2010maxim [7]

Answer:

it must be helical motion in which the charge particle will move uniformly along z axis and simultaneously it will move in circular path in xy plane.

Explanation:

Magnetic field is along z axis while velocity is in x-z plane

so we will have

F = q(\vec v \times \vec B)

so here we can say

F = q(u\hat i + w\hat k) \times (B \hat k)

so we will have

F = quB(-\hat j)

so here the net force on the charge is perpendicular to its x directional velocity along - Y direction

So due to this component of motion it will move along a circle while other component of the motion will remain uniform always

So here it is combination of two parts

1) Uniform circular motion

2) Uniform motion

So we can say that it must be helical motion in which the charge particle will move uniformly along z axis and simultaneously it will move in circular path in xy plane.

4 0
3 years ago
A 1200N load is to be lifted with 200N effort using a first class lever. At what distance
kipiarov [429]

Explanation:

Hey there!!

Let's simply work with it.

Here,

load = 1200N

Effort = 200N

Load distance = 15cm

We have,

According to the principle of lever.

L×LD = E×ED.

1200×15 = 200× ED.

18000 = 200ED.

ed =  \frac{18000}{200}

Therefore, Effort Distance = 90cm.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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