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3 years ago

Which best describes accuracy?

Physics

2 answers:

Likurg_2 [28]3 years ago

7 0

The answer is either c or b

krok68 [10]3 years ago

4 0

Not sure but i think A or C but no forsure

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A 1.80- kgkg monkey wrench is pivoted 0.250 mm from its center of mass and allowed to swing as a physical pendulum. The period f

madam [21]

Answer:

A. 1.125×10^-7 kgm^2

B. 6.64875 rad/s

Explanation:

The moment of inertia is defined as a quantity expressing a body's tendency to resist angular acceleration, which is the sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation.

A. Moment of inertia = m1✖r1^2

=1.80 x (2.5x10^-4)^2

= 6.25x10^8 x 1.80

= 1.125 x 10^-7 kgm^2.

B. w is represented as Angular speed.

V is velocity, T is time in period.

Velocity= distance / time.

V= 2.5x10^-4 / 0.940

V= 2.6595 metre per seconds

w= v/r

w= 2.6595 / 0.400

w= 6.64875 rad/s.

6 0

3 years ago

Can someone help?

laila [671]

Answer:

i) 21 cm

ii) At infinity behind the lens.

iii) A virtual, upright, enlarged image behind the object

Explanation:

First identify,

object distance (u) = 42 cm (distance between object and lens, 50 cm - 8 cm)

image distance (v) = 42 cm (distance between image and lens, 92 cm - 50 cm)

The lens formula,

$\frac{1}{v} -\frac{1}{u} =\frac{1}{f}$

Then applying the new Cartesian sign convention to it,

$\frac{1}{v} +\frac{1}{u} =\frac{1}{f}$

Where f is (-), u is (+) and v is (-) in all 3 cases. (If not values with signs have to considered, this method that need will not arise)

Substituting values you get,

i) $\frac{1}{42} +\frac{1}{42} =\frac{1}{f}\\\frac{2}{42} =\frac{1}{f}$

f = 21 cm

ii) u =21 cm, f = 21 cm v = ?

Substituting in same equation $\frac{1}{v} =\frac{1}{21} =\frac{1}{21} \\\\\frac{1}{v} = 0\\$

v ⇒ ∞ and image will form behind the lens

iii) Now the object will be within the focal length of the lens. So like in the attachment, a virtual, upright, enlarged image behind the object.

7 0

3 years ago

A rock weighs 110 N in air and has a volume of 0.00337 m3 . What is its apparent weight when submerged in water? The acceleratio

pickupchik [31]

Explanation:

It is given that,

Weight of the rock in air, W = 110 N

Since, W = mg

$m=\dfrac{W}{g}$

$m=\dfrac{110\ N}{9.8\ m/s^2}$

m = 11.22 kg

We need to find the apparent weight of the rock when it is submerged in water. Apparent weight is equal to the weight of liquid displaced i.e.

$M=d\times V$

d is the density of water, $d=1000\ kg/m^3$

V is the volume of rock, $V=0.00337\ m^3$

$M=1000\ kg/m^3\times 0.00337\ m^3$

M = 3.37 kg

The apparent weight in water, W = m - M

$W=7.85\ kg\times 9.8\ m/s^2$

W = 76.93 N

So, the apparent weight of the rock is 76.93 N. Hence, this is the required solution.

4 0

3 years ago

Which of the following is an important step in the process of conflict resolution?

4vir4ik [10]

A would be the correct answer. Its the only one to make sense since you are trying to solve the conflict!

7 0

4 years ago

Read 2 more answers

a block accelerates at 3.3 m/s^2 down a plane inclined at an angle of 27°. find the kinetic friction coefficient between the blo

finlep [7]

Answer:

0.13

Explanation:

Draw a free body diagram. There are three forces:

Weight force mg pulling down.

Normal force N pushing perpendicular to the incline.

Friction force Nμ pushing parallel up the incline.

Sum of the forces perpendicular to the incline:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of the forces parallel down the incline:

∑F = ma

mg sin θ − Nμ = ma

mg sin θ − mgμ cos θ = ma

g sin θ − gμ cos θ = a

gμ cos θ = g sin θ − a

μ = (g sin θ − a) / (g cos θ)

Given a = 3.3 m/s² and θ = 27°:

μ = (9.8 m/s² sin 27° − 3.3 m/s²) / (9.8 m/s² cos 27°)

μ = 0.13

3 0

3 years ago