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Llana [10]
3 years ago
8

A 1200N load is to be lifted with 200N effort using a first class lever. At what distance

Physics
1 answer:
kipiarov [429]3 years ago
7 0

Explanation:

Hey there!!

Let's simply work with it.

Here,

load = 1200N

Effort = 200N

Load distance = 15cm

We have,

According to the principle of lever.

L×LD = E×ED.

1200×15 = 200× ED.

18000 = 200ED.

ed =  \frac{18000}{200}

Therefore, Effort Distance = 90cm.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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A patient is administered 20 mg of iodine-131. How much of this isotope will remain in the body after 40 days if the half-life f
igor_vitrenko [27]

The formula for half-life is:

A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h}}

Where A is the amount of iodine-131 initially and after 40 days, t is time, h is half-life of the isotope.  Let's plug in our values to the equation:

A_{final}=20(\frac{1}{2})^{\frac{40}{8}=0.625g

Therefore, the patient has 0.625 grams of iodine-131 after 40 days.

4 0
3 years ago
In a real hemoglobin molecule, the tendency of oxygen to bind to a heme site increases as the other three heme sites become occu
sasho [114]
Since there are four states, then the grand partition function of the system is

Z = 1+2 e^{(0.55eV+ \alpha )/kT} +e^{(1.3eV+ 2\alpha )/kT}

where α is the chemical potential

Then, the occupancy of the system is

bar \ n=(e^{(0.55eV+ \alpha )/kT} +e^{(1.3eV+ 2\alpha )/kT})/Z

Then using this equation, \alpha =-kT(V Z_{int} /N v_{Q}) and approximating Z_int to be kT/0.00018 eV, the model would look as that attached in the figure. That is the occupancy vs. pressure graph. 

There are more occupancies when the oxygen is high (high pressure) especially in the lungs. Heme sites tend to be occupied by oxygen. 

7 0
3 years ago
Phase, color, and ductility are all examples of what type of property?
Mama L [17]
Physical properties.
7 0
3 years ago
A teacher told a learner to react benzene (CH) with chlorine (Cl₂) to
kolezko [41]

The minimum quantity of benzene, C₆H₆ needed for the reaction is 106.67 g

<h3>How to determine the theoretical yield of chlorobenzene, C₆H₅Cl</h3>

From the question given, the following data were obtained

  • Actual yield = 100 g
  • Percentage yield = 65%
  • Theoretical yield =?

Percentage yield = (Actual / Theoretical) × 100

65% = 100 / Theoretical

0.65 = Actual / Theoretical

Cross multiply

0.65 × Theoretical = 100

Divide both sides by 0.65

Theoretical = 100 / 0.65

Theoretical yield = 153.85 g

<h3>How to determine the mass of benzene, C₆H₆ needed</h3>

Balanced equation

C₆H₆ + Cl₂ → C₆H₅Cl + HCl

Molar mass of C₆H₆ = 78 g/mol

Mass of C₆H₆ from the balanced equation = 1 × 78 = 78 g

Molar mass of C₆H₅Cl = 112.5 g

Mass of C₆H₅Cl from the balanced equation = 1 × 112.5 = 112.5 g

SUMMARY

From the balanced equation above,

112.5 g of C₆H₅Cl were obtained from 78 g of C₆H₆

Therefore,

153.85 g of C₆H₅Cl will be produced from = (153.85 × 78) / 112.5 = 106.67 g of C₆H₆

Thus, the minimum amount of benzene, C₆H₆ needed for the reaction is 106.67 g

Learn more about stoichiometry:

brainly.com/question/16735180

#SPJ1

3 0
2 years ago
F F= {mango, apple, banana, orange)​
Stels [109]

Answer:

<h3>n(F) = 4</h3>

Explanation:

Cardinality of a set is the number of elements in that set. Given the set.

F= {mango, apple, banana, orange)​, we are to determine the cardinality of the set i.e the amount of fruit present in the set. Cardinality of the set F is represented as n(F).

Since there are 4 different fruit in the given set F, hence the cardinality of the set F is n(F) = 4

6 0
3 years ago
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