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timama [110]
3 years ago
13

is it possible for the gravitational force between two 50-kg objects to be less than the gravitational force between a 59-kg obj

ect and a 5-kg object? explain.
Physics
1 answer:
Eva8 [605]3 years ago
5 0

OF COURSE !  

The gravitational force between two objects doesn't ONLY depend on the product of their masses.  It also depends on the distance between them.

I'm not even going to work out the numbers for my example.  I'm just going to state without proof that at the top of the 2nd frame, the gravitational force between you and your bowling ball is greater than the gravitational force between you and the whole darn Andromeda galaxy !  My reasoning is based on the fact that your bowling ball is maybe 1 foot from your center of mass, whereas the Andromeda galaxy is more like 2.5 million light years from it.  That right there is going to give your bowling ball a big advantage when it comes to gravity !

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A student moves a box across the floor by exerting 56.7 N of force and doing 195 J of
Paha777 [63]

Answer:

A. 3.4 m

Explanation:

Given the following data;

Force = 56.7N

Workdone = 195J

To find the distance

Workdone is given by the formula;

Workdone = force * distance

Making "distance" the subject of formula, we have;

Distance = \frac {workdone}{force}

Substituting into the equation, we have;

Distance = \frac {195}{56.7}

Distance = 3.4 meters.

8 0
3 years ago
Where do you feel that you are traveling at the fastest speed when on the swing?
il63 [147K]

Answer:

C

Explanation:

I think it's C, because at that point, you are going fastest. Sorry if im wrong, hope this helps.

7 0
3 years ago
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zheka24 [161]

Answer: idk

Explanation: hahahaha

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3 years ago
A crate on a motorized cart starts from rest and moves with a constant eastward acceleration ofa= 2.60 m/s^2. A worker assists t
Leona [35]

Answer:

To obtain the power, we first need to find the work made by the force.

1) To calculate the work, we need the next equation:

\int\limits {F} \, dx

So the force is given by the problem so our mission is to find 'dx' in terms of 't'

2) we know that:

\frac{dV}{dt} = a = 2.6

So we have:

v = 2.6t

Then:

\frac{dx}{dt} = V = 2.6t\\ \\dx = 2.6t*dt

3) Finally, we replace everything:

\int\limits^{4.7}_{0} {5.4t*2.6t} \, dt

After some calculation, we have as a result that the work is:

161.9638 J.

4) To calculate the power we need the next equation:

P = \frac{W}{t}

So

P = 161.9638/4.7 = 34.46 W

8 0
3 years ago
At which point in the life cycle of a star does nuclear fusion begin?
Norma-Jean [14]
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i really hope that this helps you a lot.

8 0
3 years ago
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