answer : False
The measure of a tangent-tangent angle is one - half the difference of the measures of the intercepted arcs.
The diagram is attached below
AB and BC are the two tangents
By exterior angle theorem
∠3 = ∠2 + ∠4
So ∠2 = ∠3 - ∠4
Now we find angle 3 and 4, we know when a chord and tangent intersect at a point then the measure of angle is one half of measure of intercepted arc
∠3 = 
∠4 = 
∠2 = ∠3 - ∠4
∠2 = -
∠2 = 
The measure of a tangent-tangent angle is one half the difference of the measures of the intercepted arcs.
In order to complete the square, the leading coefficient has to be a positive 1, which it is. Now we will set the polynomial equal to 0 and move the 2 over by subtraction to isolate the x terms.
. The rule now is to take half the linear term, square it, and then add it in to both sides. Our linear term is 6. Half of 6 is 3, and 3 squared is 9, so we add 9 to both sides.
. Simplifying we have
. During this process, and the reason for it, was to create a perfect square binomial on the left which will give us the x coordinate (or the h) for our vertex. That perfect square binomial is
. Now we will move the 7 over by subtraction and set the polynomial back equal to y to get
. Our vertex, then, is (3, -7) and this is a min value since our parabola is positive and opens up like a cup that has a bottom instead of mountain that has a top. And there you go! Your answer is C
Answer:
2α^2+15α+21
Step-by-step explanation:
(5α+α²-14) + (10α +α²+ 35)
Combine like terms
α^2+α^2+5α+10α-14+35
2α^2+15α+21
Informally assess the degree of visual overlap of two numerical data distributions with similar variabilities, measuring the difference between the centers by expressing it as a multiple of a measure of variability.
- Hope this helps!
