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mars1129 [50]
2 years ago
6

Solve this question please A.S.A.P ⁉️No spamming ❗​

Physics
2 answers:
Lubov Fominskaja [6]2 years ago
7 0

Answer:

<h2>Here given is :-</h2>

<h3>Velocity (u) = 10m/s</h3><h3>Gravity (g) = 10 m/s²</h3><h3>Height (h) = ?</h3>

Explanation:

<h3>v² - u² = 2gh</h3>

<h3>0² - 10² = 2 × (-10) × h</h3>

<h3>-100 = -20 h</h3>

<h2>h =  \frac{ - 100}{ - 20}  = 5m</h2><h3>V = u + gt</h3><h3>0 = 10 - 10t</h3><h3>10t = 10</h3><h2>t =  \frac{10}{10}  = 1 \: sec</h2><h3>Total time = 2 sec</h3>
elena55 [62]2 years ago
4 0

Answer:

See below

Explanation:

vf = vo + at        when it reaches top vf = 0    vo = 10m/s      a = -9.81 m/s^2

0 =   10  + (-9.81) t  

t = 1.02 seconds to reach max

time up = time down   so    roundtrip =  2.04 seconds

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    A) ultraviolet light ---> violet light ----> red light-----> infrared light

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How long does it take an automobile traveling 66.7 km/h to become even with a car that is traveling in another lane at 52.7 km/h
tresset_1 [31]

Answer:

The  time taken is  t =  32.5 \  s

Explanation:

From the question we are told that

   The  speed  of  first car is  v_1  =  66.7 \ km/h  =  18.3 \  m/s

    The  speed  of  second car is v_2  =  52.7 \ km/h  =  14.64 \  m/s

   The  initial distance of separation is  d =  119 \ m

The distance covered by first car is mathematically represented as

     d_t =  d_i  +  d_f

Here  d_i is the initial distance which is  0 m/s

  and  d_f  is the final distance covered which is  evaluated as d_f  =  v_1 * t

So

     d_t =  0 \  m/s  +  (v_1 * t )

     d_t =  0 \  m/s  +  (18.3 * t )

The distance covered by second  car is mathematically represented as

     d_t =  d_i  +  d_f

Here  d_i is the initial distance which is  119 m

  and  d_f  is the final distance covered which is  evaluated as d_f  =  v_2* t

       d_t =  119  + 14.64 *  t

Given that the two car are now in the same position we have that

    119  + 14.64 *  t  =   0   +  (18.3 * t )

   t =  32.5 \  s

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3 years ago
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