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Kruka [31]
3 years ago
5

Which of the following describes the relationship between the weight of fluid

Physics
1 answer:
ioda3 years ago
8 0
The answer is archimedes principle
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What kind of wave is a sound wave?
kicyunya [14]
A wave sound is a longitudinal <span>wave.
HOPE THIS HELPS :)

</span>
4 0
3 years ago
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When decreasing electromagnetic radiation there is a(n)_______relationship between wavelength and frequency and the greater the
IceJOKER [234]

Answer:

Inverse proportion, greater

Explanation:

The relation between wavelength (λ) and frequency (ν) is given by

\nu = \frac{c}{\lambda }

Where c speed of light in vacuum.

We can see from this equation that wavelength and frequency are related inversely.

Now,

E= h \nu

Where 'E' is energy of electromagnetic radiation and 'h' is Planck's constant.

We can see from this equation that greater frequency (ν) will give greater electromagnetic radiation (E). As they are directly proportional.

Hence,

When decreasing electromagnetic radiation there is a(n) Inverse proportion relationship between wavelength and frequency and the greater the frequency, the greater energy the electromagnetic radiation has

5 0
3 years ago
The figure shows two 1.0 kg blocks connected by a rope. a second rope hangs beneath the lower block. both ropes have a mass of 2
lutik1710 [3]
We need first to use the formula  F=m(a+g), m iis the total mass, a is the acceleration, g is gravity pulling the blocks. So the procedure will be 
<span>m=2kg(both blocks)+500g(both ropes) → m=2.5kg </span>
<span>a=3.00m/s^2 </span>
<span>g=9.8m/s^2 </span>
<span>F=m(a+g) → F=2.5kg (3.00m/s^2 + 9.8m/s^2) → F=2.5kg (12.8m/s^2) → F=32 N 
To calculate the tension at the top of rope 1 you need to use the formula </span>T=m(a+g) so it will be <span>T=m(a+g) → T=1.5kg(12.8m/s^2) → T=19.2N 
</span>We can now calculate the tension at the bottom of rope 1 using the formula: <span>T=m(a+g) → T=1.25kg(12.8m/s^2) → T=16N 
</span>Now to find the tension at the top of rope 2 we do it like this: 
<span>T=m(a+g) → T=.25kg(12.8m/s^2) → T=3.2</span>
7 0
3 years ago
Read 2 more answers
A car with mass 1500 kg moves with constant velocity of 36 m/s. The driver sees a group of cows in front and he immediately step
Crazy boy [7]
From laws of motion:

S = ( \frac{v + u}{2} ) \times t
Where S is the distance/displacement (as you would call it) which is unknown
v = final velocity which is 0m/s (this is because the car stops)
u = initial velocity which is 36m/s (from the data given)
t = time taken for the distance to be covered and it is 6s


Substitute the values, hence:
S = ( \frac{0 + 36}{2} ) \times 6
S = (18) \times 6 \\  \\ S = 108m

But this is merely the distance he travelled in the 6 seconds he was trying to stop the car.

Therefore, the distance between the car and the cows = 160-108
Distance = 52m
6 0
4 years ago
A car travels west for 240km in 4 hours. What is the car's velocity?
lbvjy [14]
<span> answer as followed 240km/4h=60km/h </span>
6 0
3 years ago
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