A rocket weighs 1.000. N on the surface of Earth. What is its weight at a distance of two Earth radii above the

during the spin dry cycle of a washing machine, the motor slows from 90 rad/s to 30 rad/s while turning the drum though an angle

Doss [256]

Answer:

option D

Explanation:

given,

initial speed of motor, ω₁ = 90 rad/s

final speed of motor, ω₂ = 30 rad/s

angle, θ = 180 rad

angular acceleration,α = ?

using equation of rotational motion

ω₂² = ω₁ ² + 2 α θ

90² = 30² + 2 x α x 180

360 α = 7200

α = 20 rad/s²

the angular acceleration of the motor comes out to be 20 rad/s²

the correct answer is option D

5 0

2 years ago

When conducting objects (such as metals) are connected for a brief time, charge can be made to flow quite easily from one to the

sukhopar [10]

Answer:

a) charges of the opposite, b) Δq = q₄₂-q₄₁, force is repulsive

c) q = 5.27 10⁻⁵ C

Explanation:

a) In electrostatic studies it is found that charges of the same sign repel and charges of the opposite sign attract.

On the other hand, as the force between the spheres is attractive, the charges on them are of different sign

b) When the balls touch, the charges are quickly distributed between the two spheres, therefore there are two possibilities:

* if the charges were equal and as they are of the opposite sign, they are neutralized, therefore the spheres remain uncharged

The force between them is zero

* if the charges are different, a residual charge remains

Δq = q₄₂-q₄₁

that is distributed between the two spheres and the force between them is repulsive

c) For this case the charges on the two spheres is equal

q₄₁ = q₄₂ = q

the force is repulsive so the charges are of the same sign.

We can apply Coulomb's law

F = $k \frac{q_1q_2}{r^2}$

in this case

F = $k \frac{q^2}{r^2}$

q = $\sqrt{ \frac{F \ r^2}{k} }$

let's calculate

q = $\sqrt{ \frac{25 \ 1^2}{9 \ 10^{9}} }$ = $\sqrt{27.7778 \ 10^{-10}}$

q = 5.27 10⁻⁵ C

7 0

3 years ago

A child is prescribed a drug X; the recommended manufacturer’s dose is 2.50 mg/m2. The body surface area (BSA) of the child is 1

guapka [62]

Answer: 3.75 mg

Explanation:

We need a dose of 2.50 mg per square meter of BSA, and we also know that the BSA of the child is 1.50 m^2, then if the dosage should be 2.50mg for one m^2, for 1,5 m^2 we should administrate an amount of:

D = 1.5 m^2*(2.50mg/m^2) = 1.5*2.5 mg = 3.75 mg

3 0

3 years ago

If the shoe has less mass, it will experience _______________ (more, less, the same) friction as it would with more mass.

Valentin [98]

More I’m pretty sure but no promises

4 0

3 years ago

A long solenoid that has 1,140 turns uniformly distributed over a length of 0.415 m produces a magnetic field of magnitude 1.00

mezya [45]

Answer:

Therefore,

Current required is , I

$I = 0.0289\ Ampere$

Explanation:

Given:

Turns = N = 1140

length of solenoid = l = 0.415 m

Magnetic Field,

$B = 1.00\times 10^{-4}\ T$

To Find:

Current , I = ?

Solution:

If N is the number of turns in the length, the total current through the rectangle is NI. Therefore, Ampere’s law applied to this path gives

$\int {B} \, ds= Bl=\mu_{0}NI$

Where,

B = Strength of magnetic field

l = Length of solenoid

N = Number of turns

I = Current

$\mu_{0}=Permeability\ in\ free\ space=4\pi\times 10^{-7}\ Tm/A$

Therefore,

$I =\dfrac{Bl}{\mu_{0}N}$

Substituting the values we get

$I =\dfrac{1.00\times 10^{-4}\times 0.415}{4\times 3.14\times 10^{-7}\times 1140}=0.0289\ Ampere$

Therefore,

Current required is , I

$I = 0.0289\ Ampere$

3 0

3 years ago