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1 year ago

B is the midpoint of ac. bc = 3x - 1. ac = x + 3. find the value of ab

Mathematics

1 answer:

Ilia_Sergeevich [38]1 year ago

8 0

Answer:

ab=bc because b devide ac in two equal sizes

ac=ab+bc

ac=2×ab

ac =2×bc

lets substitute ac and bc there we are given

x+3=2(3x-1)

x+3=6x-2

-5x/-5=-5/-5

x=1

ab=3(1)-1

ab=2

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weqwewe [10]

Answer:

640 pounds

Step-by-step explanation:

The rest of the question is the attached figure

So, the total volume = V(cylinder ) + V(cone)

The volume of cylinder = π r² h

The volume of cone = π r² h/3

Both of the cylinder and the cone have the same diameter = 14 inches

So, the radius = 14/2 = 7 inches

The height of the cylinder is 13 inches and the height of the cone is 9 inches.

So, The volume of cylinder = π r² h = π * 7² * 13 = 2,001.2 in³

And The volume of cone = π r² h/3 = π * 7² * 9/3 = 461.8 in³

So, the total volume = 2,001.2 + 461.8 = 2,463 in³

So, the total weight = 0.26 pounds per cubic inch times the total volume

= 0.26 * 2463 = 640.38 pounds

= 640 pounds (to the nearest pound)

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3 years ago

David works at Mc Donald’s, and he made 96.75 for 10 hours of work how much does David earn per hour

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9.675

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The height of a right circular cylinder is 1.5 times the radius of the base. What is the ratio of the total surface area to the

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Let r represent the radius of cylinder.

We have been given that the height of a right circular cylinder is 1.5 times the radius of the base. So the height of the cylinder would be $1.5r$ .

We will use lateral surface area of pyramid to solve our given problem.

$LSA=2\pi r h$ , where,

LSA = Lateral surface area of pyramid,

r = Radius,

h = height.

Upon substituting our given values in above formula, we will get:

$LSA=2\pi r\cdot (1.5)r$

Now we will find the total surface area of cylinder.

$TSA=2\pi r(r+h)$

$TSA=2\pi r(r+1.5r)$

$TSA=2\pi r(2.5r)$

$\frac{TSA}{LSA}=\frac{2\pi r(2.5r)}{2\pi r(1.5r)}$

$\frac{TSA}{LSA}=\frac{2.5r}{1.5r}$

$\frac{TSA}{LSA}=\frac{25}{15}$

$\frac{TSA}{LSA}=\frac{5}{3}$

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