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3 years ago

Find the sum.

Mathematics

2 answers:

mihalych1998 [28]3 years ago

6 0

Answer:

B) 0.79

Step-by-step explanation:

.47

.32 + bring it down, like a normal addition problem

.79 bring the decimal down as well because you are just adding

Hope this helped!

Anni [7]3 years ago

4 0

Answer:

B is the correct answer... 0.79

Step-by-step explanation:

You add the ones first and then move on to the tens and add. You get 0.79

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What is the answer to 8/12 = ?/3

Luda [366]

Answer:

2/3 is the answer.

Its divided by 4...

Hope it helps!!!

6 0

3 years ago

Read 2 more answers

choose five ordered pairs whose first and second coordinates are equal. plot these points and connect them. what kind of figure

Effectus [21]

Answer:

The figure is a straight line.

The figure lies in the first and the third quadrants.

Step-by-step explanation:

Take five ordered pairs as $(1,1),(2,2),(-1,-1),(-2,-2),(3,3)$

Here, the first and second coordinates are equal.

Now, plot these points and connect them.

From the graph, it can be observed that the figure is a straight line.

Also, the figure lies in the first and the third quadrants.

Download pptx

5 0

3 years ago

What is the correct answer?

mart [117]

There are 8 marks on the line and the first line is 3 long while the second is 2 long
c. 3/8+2/8=5/8

6 0

3 years ago

Given f(x)=6x+2 find f(x+3)

Ede4ka [16]

If f(x)=6x+2,

f(x+3)=6(x+3)+2

f(x+3)=6x+18+2

f(x+3)=6x+20

3 0

3 years ago

Given: m∠LON=77 ° m∠LOM=9x+44 ° m∠MON=6x+3 ° Find ∠MON

NISA [10]

Answer:

$m\angle MON=15^o$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

$m\angle LON=m\angle LOM+m\angle MON$ ---> by addition angle postulate

substitute the given values

$77^o=(9x+44)^o+(6x+3)^o$

solve for x

$77=(15x+47)$

$15x=77-47$

$15x=30\\x=2$

Find the measure of angle MON

$m\angle MON=(6x+3)^o$

substitute the value of x

$m\angle MON=(6(2)+3)=15^o$

8 0

3 years ago