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Monica [59]
1 year ago
7

Which of these statements is true? (Select all that apply.) Any translation can be replaced by two reflections. Any translation

can be replaced by two rotations. Any rotation can be replaced by a reflection. Any reflection can be replaced by a rotation followed by a translation.
Mathematics
2 answers:
likoan [24]1 year ago
6 0
First and second one I believe
prisoha [69]1 year ago
4 0
The second one I think.
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the answer is y=6x

(6 is a constant)

Explanation:

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Which of the following is the portion of a line that starts at one point and goes off in a particular direction to infinity?
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Simplify.<br> 40 to the half power
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2✓10

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40 to the half power

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Rewrite the function f(x)=-4(x-3)^2+16 in the form f(x)=ax^2+bx+c
elena55 [62]

Answer:

f(x) = - 4x² + 24x - 20

Step-by-step explanation:

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f(x) = - 4(x - 3)² + 16 ← expand the factor using FOIL

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2 years ago
A pyramid has a square base of length 8cm and a total surface area of 144cm². Find the volume of the pyramid. (Please use Pythag
Sveta_85 [38]

Answer:

\displaystyle V_{ \text{pyramid}}= 64 \:  {cm}^{3}

Step-by-step explanation:

we are given surface area and the length of the square base

we want to figure out the Volume

to do so

we need to figure out slant length first

recall the formula of surface area

\displaystyle A_{\text{surface}}=B+\dfrac{1}{2}\times P \times s

where B stands for Base area

and P for Base Parimeter

so

\sf\displaystyle \: 144=(8 \times 8)+\dfrac{1}{2}\times (8 \times 4) \times s

now we need our algebraic skills to figure out s

simplify parentheses:

\sf\displaystyle \: 64+\dfrac{1}{2}\times32\times s = 144

reduce fraction:

\sf\displaystyle \: 64+\dfrac{1}{ \cancel{ \: 2}}\times \cancel{32}  \: ^{16} \times s = 144 \\ 64 + 16 \times s = 144

simplify multiplication:

\displaystyle \: 16s + 64 = 144

cancel 64 from both sides;

\displaystyle \: 16s = 80

divide both sides by 16:

\displaystyle \: \therefore \: s = 5

now we'll use Pythagoras theorem to figure out height

according to the theorem

\displaystyle \:  {h}^{2}  +  (\frac{l}{2} {)}^{2}  =  {s}^{2}

substitute the value of l and s:

\displaystyle \:  {h}^{2}  +  (\frac{8}{2} {)}^{2}  =  {5}^{2}

simplify parentheses:

\displaystyle \:  {h}^{2}  +  (4 {)}^{2}  =  {5}^{2}

simplify squares:

\displaystyle \:  {h}^{2}  +  16  =  25

cancel 16 from both sides:

\displaystyle \:  {h}^{2}   =  9

square root both sides:

\displaystyle \:   \therefore \: {h}^{}   =  3

recall the formula of a square pyramid

\displaystyle V_{pyramid}=\dfrac{1}{3}\times A\times h

where A stands for Base area (l²)

substitute the value of h and l:

\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times  \{8 \times 8 \}\times 3

simplify multiplication:

\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times  64\times 3

reduce fraction:

\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{ \cancel{ 3 \: }}\times  64\times \cancel{ \:  3}

hence,

\sf\displaystyle V_{ \text{pyramid}}= 64 \:  {cm}^{3}

8 0
2 years ago
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