15 POINTS PLS HELP

Estimate the measure of the clockwise angle formed by the minute hand and the second hand, then classify the angle.

irga5000 [103]

A. 54°; acute is the answer

8 0

3 years ago

What is the sum of interior angles for a nonagon

alexira [117]

Remember your prefixes! They help a lot, because there is a formula for this particular problem. Nonagon refers to a shape with 9 sides.

The number of triangles a polygon has is represented by the formula:
(n-2)

Where "n" is the number of sides. If you ever forget what you subtract "n" by think of a triangle. It has 3 sides, so it is only logical that you should only have 1 triangle (subtract by 2). So, what is the sum of the interior angles of a triangle, 180°. So the formula looks like this:

Sum of Interior Angles = 180°(n-2)
180°(9-2)
180°(7) = 1260° is the sum of interior angles for a nonagon!

5 0

3 years ago

Find the volume of the sphere . (Geometry)

asambeis [7]

Answer:

V = 32/3 pi

Step-by-step explanation:

The volume of a sphere is given by

V= 4/3 pi r^3

We know the radius is 2

V = 4/3 pi (2)^3

V = 4/3 pi (8)

V = 32/3 pi

6 0

3 years ago

Complete parts (a) through (c) below. (a) Determine the critical value(s) for a right-tailed test of a population mean at t

olga_2 [115]

Answer:

a) The critical value on this case would be $t_{crit}=1.325$

b) The critical value on this case would be $t_{crit}=-1.345$

c) The critical values on this case would be $t_{crit}=\pm 2.201$

Step-by-step explanation:

Part a

The system of hypothesis on this case would be:

Null hypothesis: $\mu \leq \mu_0$

Alternative hypothesis: $\mu > \mu_0$

Where $\mu_0$ is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, on this case that is given df=20. Since its an upper tailed test we need to find a value a such that:

$P(t_{20}>a) = 0.1$

And we can use excel in order to find this value with this function: "=T.INV(0.9,20)". The 0.9 is because we have 0.9 of the area on the left tail and 0.1 on the right.

The critical value on this case would be $t_{crit}=1.325$

Part b

The system of hypothesis on this case would be:

Null hypothesis: $\mu \geq \mu_0$

Alternative hypothesis: $\mu < \mu_0$

Where $\mu_0$ is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, given by:

$df=n-1=15-1=14$

Since its an lower tailed test we need to find b value a such that:

$P(t_{14}$

And we can use excel in order to find this value with this function: "=T.INV(0.1,14)". The 0.1 is because we have 0.1 of the area accumulated on the left of the distribution.

The critical value on this case would be $t_{crit}=-1.345$

Part c

The system of hypothesis on this case would be:

Null hypothesis: $\mu = \mu_0$