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Jet001 [13]
1 year ago
5

Find the distance between the points. Give an exact answer

Mathematics
1 answer:
never [62]1 year ago
4 0

Answer: 2\sqrt{10} \approx 6.325

Step-by-step explanation:

\sqrt{(-9-(-11))^2 +(-3-(-9))^2}=2\sqrt{10} \approx 6.325

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Noha, Sarah, and Karima are sisters. Noha is 3 years older than Sarah.
Virty [35]

Answer:

25 years old

Step-by-step explanation:

karima is 20 years old

Sarah is 2 years older than karima (20+2= 22)

Noha is 3 years older than Sarah

if sara is 22 then noha is 22+3=25

5 0
2 years ago
PLEASE PLEASE PLEASE HELP FAST!!!!!!!!!! WILL REPORT ANY TROLLS
worty [1.4K]

Answer:

i think its 1.5 im not sure tho 1.5 sounds the best

Step-by-step explanation:

6 0
2 years ago
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What is the sum of 506,211 and 424,809
Allushta [10]
506,211+424,809=931,020 sum means add hope this helps
6 0
3 years ago
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Find the quotient of 2.632 x 10^4 and 2 x 10^-7
givi [52]
(2.632\cdot10^4):(2\cdot10^{-7})=(2.632:2)\cdot(10^4:10^{-7})\\\\=1.316\cdot10^{4-(-7)}=1.316\cdot10^{4+7}=\boxed{1.316\cdot10^{11}}
6 0
2 years ago
The general equation for a circle is a(x^2 + y^2) + bx + cy + d = 0. There is exactly one circle passing through the points (3,-
lidiya [134]

Answer:

The equation for this circle is 2c(x²+y²) - 8cx + cy = 0

Step-by-step explanation:

We can solve this problem replacing each of the points in the general equation and then solving the system of equations.

The fact that the circle passes by the point (3,-2) means that when x = 3, y = -2. So:

a(3^{2} + (-2)^2) + 3b - 2c + d = 0

13a+ 3b - 2c + d = 0

For (1, -2)

a(1^{2} + (-2)^2) + b - 2c + d = 0

5a + b - 2c + d = 0

For (0,0)

a(0^{2} + (0)^2) + 0b - 0c + d = 0

d = 0

Now we have to find a,b,c, from the following equations

13a+ 3b - 2c = 0

5a + b - 2c = 0

Since we have variables and 2 equations, i am going to write a and b as functions of c.

13a + 3b = 2c

5a + b = 2c

I will write b in the second equation as a function of a and c, and replace in the first equation

b = 2c - 5a

---------

13a + 3(2c-5a) = 2c

13a + 6cc -15a = 2c

-2a = -4c *(-1)

2a = 4c

a = 2c

-----------

b = 2c - 5a

b = 2c - 5(2c)

b = -8c

The solution for the system is (a,b,c) = (2c, -8c, c). So the equation for this circle is 2c(x²+y²) - 8cx + cy = 0

6 0
2 years ago
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