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sveticcg [70]
3 years ago
7

Find two mixed numbers so that the sum is 7 2/8 and the difference is 2 4/8

Mathematics
1 answer:
olga_2 [115]3 years ago
6 0
So let's name the numbers x and y.

we know that their sum, x+y is 7\frac{2}{8}

and that that their difference, x-y is 2\frac{4}{8}

so, from the last one we can find out x:

x-y=2\frac{4}{8}
x=2\frac{4}{8}+y


we can substitute this into the first one:

2\frac{4}{8}+y+y = 7\frac{2}{8}

2\frac{4}{8}+2y = 7\frac{2}{8}

2y=4\frac{6}{8} (7-2=5, but you have to "borrow" one because the fraction of the number from which you substract is smaller than of the other number)

so y=2\frac{3}{8}

then x will be
x=2\frac{4}{8}+2\frac{3}{8}
x=4\frac{7}{8}









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