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zimovet [89]
3 years ago
13

What is the maximum value of the equation -5x2 + 100x +4000

Mathematics
1 answer:
ANEK [815]3 years ago
8 0

Answer:

114

Step-by-step explanation:

go to calculator

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What is the least common denominator of 1/5a +1=3/10
dexar [7]

Answer:

points

Step-by-step explanation:

6 0
2 years ago
4 people can stay at a hotel for a week for 42£. Find the hotel cost bill for 3
satela [25.4K]

Answer:

31.5

Step-by-step explanation:

divide 42 by 4 you would get 10.5, then multiple 10.5 by 3 and you would get 31.5 thats the answer

4 0
2 years ago
Solve the inequality (question 30 please, already solved others)
STALIN [3.7K]

\bf \cfrac{1}{4}n+12 \geqslant \cfrac{3}{4}n-4\implies \cfrac{1}{4}n+16 \geqslant \cfrac{3}{4}n\implies 16\geqslant \cfrac{3n}{4}-\cfrac{1n}{4}\implies 16\geqslant \cfrac{3n-1n}{4} \\\\\\ 16\geqslant\cfrac{2n}{4}\implies 16\geqslant \cfrac{n}{2}\implies 32 \geqslant n

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2 years ago
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1. Solve the system of equations algebraically.
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Hello,
Please, see the attached files.
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8 0
3 years ago
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angel's dad bought a television for her completing all of her digital learning day lesson. he want to warp the gift. the box mea
atroni [7]

Answer: 13 sheets of paper

Step-by-step explanation:

We are given the dimensions of the box and the wrap paper:

Box:

(56 in)(8 in)(36 in)

Warp paper:

(26 in)(17 in)

Now we need to find the surface area of the box and the area of the wrap paper:

Box:

surface_{1}=(56 in)(8 in)(2)=896 in^{2}

surface_{2}=(8 in)(36 in)(2)=576 in^{2}

surface_{3}=(56 in)(36 in)(2)=4032 in^{2}

surface-area=896 in^{2}+576 in^{2}+4032 in^{2}=5504 in^{2}

Warp paper:

area=(26 in)(17 in)=442 in^{2}

Dividing the area of the box by the area of the paper:

\frac{surface-area}{area}=\frac{5504 in^{2}}{442 in^{2}}=12.45 \approx 13

This means Angel's dad needs to purchase 13 sheets of wrapping paper.

4 0
3 years ago
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