the student has left 75 because if you add 5 and 70 it gives you $75 that's how much the student had left.
Answer:
<h2>4×4+
<em><u>4</u></em></h2>
Step-by-step explanation:
<em><u>hope</u></em><em><u> </u></em><em><u>its</u></em><em><u> </u></em><em><u>helpful</u></em>
Answer:
- y = (x - 4)(x + 2i)(x - 2i)(x + √3)(x - √3) Possible answer
- y = (x - 4)(x^2 + 4)(x^2 - 3) Possible answer
Step-by-step explanation:
The simplest answer is that 2i cannot be a lone root. It must have a twin that is - 2i
√3 has the same sort of rule. It cannot be a root all by itself. It also must have a twin, in this case -√3
So the answer must be
(x - 4)(x + 2i)(x - 2i)(x + √3)(x - √3) <<< Possible answer
but this can be reduced even further.
- (x + 2i)(x - 2i) = x^2 - x*2i + x*2i - 4i^2
- (x + 2i)(x - 2i) = x^2 - 4(i)^2
- (x + 2i)(x - 2i) = x^2 + 4. Remember i^2 = - 1
By a similar method (x - √3)(x + √3) = x^2 - 3
So the polynomial is reduced to
(x - 4)(x^2 + 4)(x^2 - 3) <<<< Answer
If this is not among your answers and the factored form is not either, please tell me what is.
8x+324 is the answer, all you have to do is multiple 6 times 54
Answer:
<span>y=<span><span><span>log<span>(x)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8)</span></span></span></span>
Explanation:
write as : <span>y=50000<span><span>(0.8)</span>x</span></span>
Taking logs:
<span><span>log<span>(y)</span></span>=<span>log<span>(50000)</span></span>+<span>log<span>(.<span><span>(0.8)</span>x</span>.)</span></span></span>
But <span>log<span>(.<span><span>(0.8)</span>x</span>.)</span></span> is the same as <span>x<span>log<span>(0.8)</span></span></span>
Thus
<span>x=<span><span><span>log<span>(y)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8<span>)
</span></span></span></span></span>Now swap the x'x and the y's giving:<span><span><span><span><span>
</span></span></span></span></span>
<span>y=<span><span><span>log<span>(x)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8<span>)
my teacher helped a little bit
</span></span></span></span></span>
