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3 years ago

How many centigrams are in 6 hectograms? Use the metric table to help answer the question.

Mathematics

2 answers:

Marta_Voda [28]3 years ago

4 0

There are 60000 centigrams in 6 hectograms.

Over [174]3 years ago

4 0

Answer:

There are 60000 centigrams in 6 hectograms

Step-by-step explanation:

We know that 1 hectogram=10000 centigrams

Multiplying both sides by 6

⇒ 6 hectograms=6×10000 centigrams

⇒ 6 hectograms=60000 centigrams

Hence, there are 60000 centigrams in 6 hectograms

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What is the answer to this?

alexdok [17]

Answer:

x < 2.5
x > 2.5

Step-by-step explanation:

One way to do this is to try a number for x and see if it makes the inequality true. A suitable number here is x=0. This value of x is less than 2.5.

For x=0, you have ...

5 > -5 . . . . . true; the solution space is x < 2.5

For x=0, you have ...

-25 > -5(2.5)

-25 > -12.5 . . . . . false; the solution space is x > 2.5

_____

<em>Alternate solution</em>

Subtract 5:

-4x > -10

Divide by -4

x < 2.5

Divide by -5:

5 < x +2.5

Subtract 2.5

2.5 < x

x > 2.5

6 0

2 years ago

Describe the location of the point having the following coordinates. negative abscissa, zero ordinate between Quadrant II and Qu

Marianna [84]

Answer:

The location of the point is between Quadrant II and Quadrant III

Step-by-step explanation:

we know that

The abscissa refers to the x-axis and ordinate refers to the y-axis

in this problem we have

the coordinates of the point are $(-x,0)$

see the attached figure to better understand the problem

The location of the point is between Quadrant II and Quadrant III

6 0

3 years ago

I need help I don’t understand this

alex41 [277]

This is the solution hope you can understand, i apologize for the bad handwriting

4 0

3 years ago

The least-squares regression model y =−3.4+5.2x and correlation coefficient r=−0.66 were calculated for a set of bivariate data

Makovka662 [10]

Answer:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For this case the value of r = -0.66

Now we can calculate the determination coeffcient:

$r^2 = (-0.66)^2 = 0.4356$

And then we can conclude that 43.56% of the variation in y can be explained by the explanatory variable

And then 100-43.56 = 56.44 % of the variation in y that cannot be explained by the explanatory variable

Step-by-step explanation:

For this case we need to calculate the slope with the following formula:

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

$\bar x= \frac{\sum x_i}{n}$

$\bar y= \frac{\sum y_i}{n}$

And we can find the intercept using this:

$b=\bar y -m \bar x$

And the model obtained for this case is:

$y = -3.4 +5.2 x$

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

And in order to calculate the correlation coefficient we can use this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For this case the value of r = -0.66

Now we can calculate the determination coeffcient:

$r^2 = (-0.66)^2 = 0.4356$

And then we can conclude that 43.56% of the variation in y can be explained by the explanatory variable

And then 100-43.56 = 56.44 % of the variation in y that cannot be explained by the explanatory variable

8 0

3 years ago

Is it possible for two planes to intersect in exactly one point

Strike441 [17]

Two planes intersect at a line. Not a point.

8 0

3 years ago