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Alinara [238K]
3 years ago
9

Describe the location of the point having the following coordinates. negative abscissa, zero ordinate between Quadrant II and Qu

adrant IV Quadrant II between Quadrant I and Quadrant IV between Quadrant II and Quadrant III

Mathematics
1 answer:
Marianna [84]3 years ago
6 0

Answer:

The location of the point is between Quadrant II and Quadrant III

Step-by-step explanation:

we know that

The abscissa refers to the x-axis  and ordinate refers to the y-axis

so

in this problem we have

the coordinates of the point are (-x,0)

see the attached figure to better understand the problem

The location of the point is between Quadrant II and Quadrant III

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1. B

2. B

3. A

4. C
5. B

6. A

 

WORKINGS

 

QUESTION 1

7 pt 1c + 4pt 1c (pt for Pints; c for Cups)
= 7pt + 1c + 4pt + 1c

 

Collecting like terms

= 7pt + 4pt + 1c + 1c

= 11pt + 2c

 

1pt = 2c

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11pt 2c = 11pt + 1pt

= 12 pt (OPTION B)

 


QUESTION 2

7c 3fl oz – 3c 4fl oz (c for Cups; oz for Ounce)
= 7c + 3fl oz – (3c + 4fl oz)

= 7c + 3fl oz – 3c – 4fl oz

 

Collecting like terms

= 7c – 3c + 3fl oz – 4fl oz

= 4c – 1fl oz

 

1c = 8fl oz

Therefore, 4c can be rewritten as 3c + 8fl oz

 4c – 1fl oz = 3c + 8fl oz – 1fl oz

= 3c + 7fl oz

= 3c 7fl oz (Option B)

 

 

QUESTION 3

4lb 4oz – 2lb 7oz (lb for Pounds; oz for Ounce)

= 4lb + 4oz – (2lb + 7oz)

= 4lb + 4oz – 2lb – 7oz

 

Collecting like terms

= 4lb – 2lb + 4oz – 7oz

= 2lb – 3oz

 

1lb = 16oz

Therefore, 2lb can be rewritten as 1lb + 16oz

2lb – 3oz = 1lb + 16oz – 3oz

= 1lb + 13oz

= 1lb 13oz (Option A)





QUESTION 4

7T 200lb – 2T 700lb (T for Tons; lb for Pounds)

= 7T + 200lb – (2T + 700lb)

= 7T + 200lb – 2T – 700lb

 

Collecting like terms

= 7T – 2T + 200lb – 700lb

= 5T – 500lb

1T = 2,000lb

Therefore, 5T can be rewritten as 4T + 2,000lb

5T – 500lb = 4T + 2,000lb – 500lb]

= 4T + 1,500lb

= 4T 1,500lb (Option C)

 

 

QUESTION 5

7 d 12 h – 5 d 18 h (d for Days; h for Hours)
= 7d + 12h – (5d + 18h)

= 7d + 12h – 5d – 18h

 

Collecting like terms

= 7d – 5d + 12h – 18h

= 2d – 6h

 

1d = 24h

Therefore, 2d can be rewritten as 1d + 24h

2d – 6h = 1d + 24h – 6h

= 1d + 18h

= 1d 18h (Option B)

 

QUESTION 6
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= 3h + 42min – (1h + 12min)

= 3h + 42min – 1h – 12min

 

Collecting like terms

3h – 1h + 42min – 12min
= 2h + 30min

= 2h 30min (Option A) 

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