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krok68 [10]
2 years ago
6

True of false that the memory of laptop is normally measured in kilobytes

Computers and Technology
1 answer:
sertanlavr [38]2 years ago
3 0

Answer:

false

Explanation:

It's usually measured in Megabytes(MB) or Gigabyte (GB)

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Perform algorithm time measurement for all three quadratic sorting algorithms for Best Case (already sorted), Average Case (rand
Kaylis [27]

Answer:

Experiment size : 50,000

==================================

Selection sort :

---------------------------------------------------------

Worst case : 0.162

Average case : 0.116

Best case : 0.080

Insertion sort :

---------------------------------------------------------

Worst case : 0.162

Average case : 0.116

Best case : 0.080

Bubble sort:

--------------------------------------------------------

Worst case : 0.211

Average case : 0.154

Best case : 0.117

Experiment size : 100,000

==================================

Selection sort :

---------------------------------------------------------

Worst case : 0.316

Average case : 0.317

Best case : 0.316

Insertion sort :

---------------------------------------------------------

Worst case : 0.316

Average case : 0.317

Best case : 0.316

Bubble sort:

--------------------------------------------------------

Worst case : 0.482

Average case: 0.487

Best case : 0.480.

Experiment size : 200,000

==================================

Selection sort :

---------------------------------------------------------

Worst case : 1.254

Average case : 1.246

Best case : 1.259

Insertion sort :

---------------------------------------------------------

Worst case : 1.254

Average case : 1.246

Best case : 1.259

Bubble sort:

--------------------------------------------------------

Worst case : 1.990

Average case : 2.009.

Best case : 1.950

Explanation:

[NB: since it is very long there is the need for me to put it it a document form. Kindly check the doc. Files. The file A is the sort Analysis.Java file and the file B is the sort.Java file].

The concept of algorithm time measurement strictly depends on the following;

=> The measurement of time, space or energy on different sizes.

=> Plotting of the measurements and characterizing them.

=> Running or implementation of the algorithm.

Programming language such as Java can be used in accessing the operating system clock and Java had two static methods.

KINDLY CHECK BELOW FOR THE ATTACHMENT.

Download doc
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> doc </span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> doc </span>
5 0
3 years ago
To change the backround color of a page, which tab would you use?
ivann1987 [24]
I have concluded the answer is a
4 0
3 years ago
Read 2 more answers
When using a calculator be sure to press ____ first.​
matrenka [14]

Answer:

A. C to clear any previous calculations.

hope it helps...

6 0
3 years ago
Read 2 more answers
When two files are linked together, the __________ file receives the data from another workbook.?
Ket [755]
When two files are linked together, the <u>d</u><span><u>estination </u></span>file receives the data from another workbook.

If i'm not wrong.

3 0
3 years ago
Express the following binary numbers in hexadecimal. (a) %100011100101 (b) %1011001111 (show work)
Lapatulllka [165]

Answer:

(100011100101)_{2} = (8E5)_{16} = %8E5

(1011001111) = (2CF)_{16} = %2CF

Explanation:

Binary and hexadecimal values have the following pair equivalences.

(0000)_{2} = (0)_{16}

(0001)_{2} = (1)_{16}

(0010)_{2} = (2)_{16}

(0011)_{2} = (3)_{16}

(0100)_{2} = (4)_{16}

(0101)_{2} = (5)_{16}

(0110)_{2} = (6)_{16}

(0111)_{2} = (7)_{16}

(1000)_{2} = (8)_{16}

(1001)_{2} = (9)_{16}

(1010)_{2} = (A)_{16}

(1011)_{2} = (B)_{16}

(1100)_{2} = (C)_{16}

(1101)_{2} = (D)_{16}

(1110)_{2} = (E)_{16}

(1111)_{2} = (F)_{16}

We convert from binary to hexadecimal selecting groups of 4 binary from the binary code, from the least significant bits(at the right) to the most significant bits(at the left). The conversion is an hexadecimal "string" from the last group you converted to the first. So:

(a) %100011100101

(0101)_{2} = (5)_{16}

(1110)_{2} = (E)_{16}

(1000)_{2} = (8)_{16}

So

(100011100101)_{2} = (8E5)_{16}

(b) %1011001111

(1111)_{2} = F_{16}

(1100)_{2} = C_{16}

(10)_{2} = (0010)_{2} = 2_{16}

(1011001111) = (2CF)_{16}

7 0
3 years ago
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