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Roman55 [17]
1 year ago
15

The function f(x) = (x − 4)(x − 2) is shown. What is the range of the function?

Mathematics
1 answer:
leonid [27]1 year ago
8 0

The range of the quadratic function is [-1, ∞) after plotting the function on the coordinate plane.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

It is given that:

The function is:

f(x) = (x - 4)(x - 2)

The above function is a quadratic function.

The above function can be written as:

f(x) = x² - 6x + 8

From the graph,

The minimum value of graph at x = 3 is y = -1

The range of the function is [-1, ∞)

Thus, the range of the quadratic function is [-1, ∞) after plotting the function on the coordinate plane.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

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Given collinear points E, F and G such that point F is the midpoint of segment EG. Find the new length of EG given that EF =5x+9
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Answer:

The length of EG is 58 units

Step-by-step explanation:

The midpoint of a segment divides it into two equal part

Let us use this rule to solve our question

∵ E, F, and G are collinear points

∵ Point F is the midpoint of segment EG

→ That means F divides EG into 2 equal segments EF and FG

∴ EF = FG

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∴ 5x + 9 = 3x + 17

→ Subtract 3x from both sides

∵ 5x - 3x + 9 = 3x - 3x + 17

∴ 2x + 9 = 17

→ Subtract 9 from both sides

∴ 2x + 9 - 9 = 17 - 9

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→ Divide both sides by 2 to find x

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∴ x = 4

→ Substitute x by 4 in EF and FG to find their lengths

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∵ FG = 3(4) + 17 = 12 = 17 = 29

∵ EG = EF + FG

∴ EG = 29 + 29 = 58

∴ The length of EG is 58 units

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