Answer:
no solution
Step-by-step explanation:
Answer:
4cm^2
Step-by-step explanation:
First we need to find the length of the height of the triangle using Pythagoras:
a^2+b^2=c^2 (Substitute in what we have)
a^2+3√2(^2)=2√5(^2) = a^2 + 18 = 20 -> 20-18=2 √2=BD
Now we can find the area:
AD+DC= 3√2 + √2 = 4√2 x √2 = 8/2 = 4
We know that
surface area=area of the base+4*[area of one lateral triangle side]
area of the base=b²
b is the side length of the square
b=14 cm
area of the base=14²-----> 196 cm²
area of one lateral triangle side=b*h/2
b is the side length of the square
b=14 cm
h is the height of the lateral triangle side
h is equal to the slant height
h=15 cm
area of one lateral triangle side=14*15/2----> 105 cm²
surface area=196+4*[105]------> 616 cm²
the answer is
the surface area is 616 cm²
Answer:
(x, y, z) =(1, -1,2)
Step-by-step explanation:
.............
B=5
Hope this helps!
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