Answer:
C. Test for Goodness-of-fit.
Step-by-step explanation:
C. Test for Goodness-of-fit would be most appropriate for the given situation.
A. Test Of Homogeneity.
The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.
B. Test for Independence.
The chi square is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.
C. Test for Goodness-of-fit.
The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.
Answer:
II. Longitud, L = 70 metros.
I. Ancho = 55 metros.
Step-by-step explanation:
Deje que la longitud del rectángulo sea L.
Deje que el ancho del rectángulo sea W.
Dados los siguientes datos;
Perímetro del rectángulo = 250 m
Traduciendo el problema verbal a una expresión algebraica, tenemos;
W = L - 15
Matemáticamente, el perímetro de un rectángulo viene dado por la fórmula;
P = 2 (largo + ancho)
250 = 2 (L + L - 15)
250 = 2 (2L - 15)
250 = 4L - 30
4L = 250 + 30
4L = 280
L = 280/4
Longitud, L = 70 m
Para encontrar el ancho;
W = L - 15
W = 70 - 15
Ancho = 55 m
Well the remainder more possible dividing by six would be 9.3 I hope i helped.
Answer:
15m below sea level
Step-by-step explanation:
Given data
Distance of eagle from sea= 20m
Distance of fish from eagle = 35m
Required
The distance of the fish from below the sea level
= 35-20
= 15m
Hence the fish is 15m below sea level
