2 years ago

Prove the identity (x+y)^-2xy=x^2+y^2

1 answer:

8 0

proooooof is in picture....

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sineoko [7]

Answer:

$\large\boxed{\dfrac{27}{80}}$

Step-by-step explanation:

Put x = 3, y = 2 and z = 5 to the given expression $10x^3y^{-5}z^{-2}$ :

$10(3^3)(2^{-5})(5^{-2})\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{10(27)}{(2^5)(5^2)}=\dfrac{270}{(32)(25)}=\dfrac{270}{800}=\dfrac{27}{80}$

7 0

2 years ago

prisoha [69]

Answer:

Increasing

−5<x<−1

−1<x<1

Decreasing

4<x<7

−8<x<−5

Neither Increasing nor Decreasing

1<x<4

Step-by-step explanation:

8 0

2 years ago

kirill115 [55]

Answer is (2x)(12)(54)

8 0

3 years ago

aniked [119]

Answer: X= 68

Just took the test

7 0

3 years ago

Burka [1]

Answer: 300

Explanation: $13.00 x 20 + 40 I think

3 0

2 years ago