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levacccp [35]
2 years ago
9

Prove the identity (x+y)^-2xy=x^2+y^2

Mathematics
1 answer:
Natali5045456 [20]2 years ago
8 0

proooooof is in picture....

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Que How does your tessellation with triangles relate to hexagons and tessellating the plane? Type your response in the space bel
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For a regular tessellation, the shapes can be duplicated infinitely to fill a plane such that there is no gap. The only shapes that can form regular tessellations are equilateral traingle(all sides are equal. This means that it can be turned to any side and it would remain the same), square and regular hexagon. Looking at the given options, we have

Shape Tessellate?

Octagon No

Hexagon Yes

Pentagon No

Square Yes

Triangle No(unless it is specified that it is an equilateral triangle)

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What is the answer to this questions
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The answer would be B
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Gail, Lucas, and Joel are playing a number game where they must draw a card with a number on it. Then they compare the numbers o
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Answer:

90

Step-by-step explanation:

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Write a linear equation given a slope of 6 and a y-intercept of 1/2
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3 years ago
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Suppose that a factory manufactures only tables and chairs and that the profit on one chair is $15 and on the table is $20. Each
Leya [2.2K]

Answer:

The data we have is:

Profit per chair = $15

Profit per table = $20

Chair needs: 1 large pice, 2 small pieces.

Table needs: 2 large pieces, 2 small pieces.

You have 6 large pieces and 8 small pieces, and you want to maximize the profit.

Let's define:

T = # of tables

C = # of chairs.

Total profit:

P = C*$15 + M*$20

The number of chairs that you can make is given by:

0 ≤ C ≤ 4

If you make 4 chairs, the profit is:

P = 4*$15 = $60

And there will be 2 large pieces left.

Now for the tables.

0 ≤ T ≤ 3

If you make 4 tables, the profit will be:

P = 3*$20 = $60 (same as before)

And there will be two small pieces left.

Then we want to use a medium number of tables and chairs, we can not use the maximum for any of those, the first thing we should try is:

we ideally would want to use all the pieces that we have.

8 small, 6 large:

Then we can make:

2 tables: we use 4 large pieces and 4 small pieces.

T = 2

And we have left 2 large pieces and 4 small pieces.

The leftover is enough to make two chairs.

C = 2.

In this case, where we used all our materials, the profit will be:

P = 2*$15 + 2*$20 = $30 + $40 = $70

The profit is maximized when we make 2 tables and two chairs.

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3 years ago
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