If there are 4 marbles left over each time, then we can forget about them for now.
So the question is, what is the smallest number than can be divided into 6,7 and 8?
the numbers have only one non-1 divisor in common: both 6 and 8 are divisible by 3.
so for our purposes we can "delete" one 2 and ask:
what is the smallest number than can be divided into 3,7 and 8 ?
There are no more divisors in common, so we just have to multiply them: 3*7*8=21*8=168
and the 4 marbles "extra"? We add them to this sum.
the the smallest possible number in the box is 168+4=172.
Answer:
a. $1.66
Step-by-step explanation:
We have been given that Health and Heart Club charges $259 per year. A person has 3 visits per week. We are asked to find the cost of per visit to Health and Heart Club.
We know that there are 52 weeks in one year. So total visits in one year would be 3 times 52 that 
visits.
Now, we will divide total cost by 156 to find cost per visit.
Rounding to nearest hundredths, we will get:
Therefore, the cost per visit is $1.66 and option 'a' is the correct choice.
Answer:
The first one is 12
second one is 1
third one is 23
last one 5
Step-by-step explanation:
1) Determine the GCF of the numbers 96 and 88
=> Decompose each number in their prime numbers:
=> 96 = (2^5)(3)
=> 88 = (2^3) (11)
=> GCF of 96 and 88 = 2^3 = 8
2) Determine the GCF of the letters, x^2 and x
=> x
3) Conclude the GCF of the terms is 8x
4) Now you can factor the expression by dividing each term by the GCF, 8x:
96 x^2 / (8x) = 12x
88x / (8x) = 11
So, the factored form is (8x) (12x + 11)
