we know that A has 60% of salt, so if way we had "x" amount of ounces of A solution the amount in it will be 60% of "x", or namely (60/100)*x = 0.6x.
Likewise for solution B if we had "y" ounces of it, the amount of salt in it will be (75/100) * y or 0.75y, thus
![\begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{oz of }}{amount}\\ \cline{2-4}&\\ A&x&0.60&0.6x\\ B&y&0.75&0.75y\\ \cline{2-4}&\\ mixture&60&0.65&39 \end{array}~\hfill \begin{cases} x+y=60\\ 0.6x+0.75y=39 \end{cases} \\\\\\ \stackrel{\textit{since we know that}}{x+y=60}\implies y = 60 - x~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.6x+0.75(60-x)=39}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Blcccl%7D%20%26%5Cstackrel%7Bsolution%7D%7Bquantity%7D%26%5Cstackrel%7B%5Ctextit%7B%5C%25%20of%20%7D%7D%7Bamount%7D%26%5Cstackrel%7B%5Ctextit%7Boz%20of%20%7D%7D%7Bamount%7D%5C%5C%20%5Ccline%7B2-4%7D%26%5C%5C%20A%26x%260.60%260.6x%5C%5C%20B%26y%260.75%260.75y%5C%5C%20%5Ccline%7B2-4%7D%26%5C%5C%20mixture%2660%260.65%2639%20%5Cend%7Barray%7D~%5Chfill%20%5Cbegin%7Bcases%7D%20x%2By%3D60%5C%5C%200.6x%2B0.75y%3D39%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bsince%20we%20know%20that%7D%7D%7Bx%2By%3D60%7D%5Cimplies%20y%20%3D%2060%20-%20x~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bsubstituting%20on%20the%202nd%20equation%7D%7D%7B0.6x%2B0.75%2860-x%29%3D39%7D)
![0.6x+45-0.75x=39\implies -0.15x+45=39\implies -0.15x=-6 \\\\\\ x = \cfrac{-6}{-0.15}\implies \boxed{x = 40} \\\\\\ \stackrel{\textit{we know that}}{y = 60 - x}\implies y = 60-40\implies \boxed{y = 20}](https://tex.z-dn.net/?f=0.6x%2B45-0.75x%3D39%5Cimplies%20-0.15x%2B45%3D39%5Cimplies%20-0.15x%3D-6%20%5C%5C%5C%5C%5C%5C%20x%20%3D%20%5Ccfrac%7B-6%7D%7B-0.15%7D%5Cimplies%20%5Cboxed%7Bx%20%3D%2040%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bwe%20know%20that%7D%7D%7By%20%3D%2060%20-%20x%7D%5Cimplies%20y%20%3D%2060-40%5Cimplies%20%5Cboxed%7By%20%3D%2020%7D)
Slope : -1
y-intercept : (0,4)
A reflection is a common type of transformation. To reflect a point across the<em> x-axis,</em> we consider this axis to be a mirror. On the other hand, if you want to reflect a point across the <em>y-axis, </em>you need to consider this axis to be a mirror. A coordinate grid is the <em>rectangular coordinate system</em>. Just as we can represent real numbers by points on a real number line, we can represent ordered pairs of real numbers by points in a plane called the <em>rectangular coordinate system</em>, or <em>the Cartesian plane</em>. So:
<h2>1. Point B.</h2>
If you reflect a point across the x-axis, the x-coordinate remains the same, but the y-coordinate changes into its opposite. So, if we have a point
, the reflection of this point across the x-axis is the point
. Finally, our point A
changes into:
Point B: ![(-2,3)](https://tex.z-dn.net/?f=%28-2%2C3%29)
<h2>2. Point C.</h2>
If you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate changes into its opposite. So, if we have a point
, the reflection of this point across the y-axis is the point
. Finally, our point A
changes into:
Point C: ![(2,-3)](https://tex.z-dn.net/?f=%282%2C-3%29)
_____________________
<h3><em>Below are illustrated all these points in the coordinate grid.</em></h3>
The range of possible values is all numbers less than or equal to -2.5
Step-by-step explanation:
4.00x + 5.75y = 4.70
x + y = 58.75
I dont know the answer but I believe that is the formula