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3 years ago

Which number is a solution of the inequality? b > 11.3; 9 –14 15 4

1 answer:

6 0

$b > 11.3\\\\9-NOT,\ because\ 9\ is\ not\ greater\ than\ 11.3\\-14-NOT,\ because\ -14\ is\ not\ greater\ than\ 11.3\\15-YES,\ because\ 15>11.3\\4-NOT,\ because\ 4\ is\ not\ greater\ than\ 11.3\\\\Answer:\ \boxed{15}$

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4. Dean Pelton wants to perform calculations to impress the accreditation consultants, but upon asking for information about GPA

Leya [2.2K]

Answer:

the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

Step-by-step explanation:

Let assume that n should represent the number of the students

SO, $\bar x$ can now be the sample mean of number of students in GPA's

To obtain n such that $P( \bar x \leq 2.3 ) \leq .04$

⇒ $P( \bar x \geq 2.3 ) \geq .96$

However ;

$E(x) = \int\limits^4_2 Dx (2+e^{-x} ) 4x = D \\ \\ = D(e^{-x} (e^xx^2 - x-1 ) ) ^D_2 = 12.314 D$

$E(x^2) = D\int\limits^4_2 (2+e^{-x})dx \\ \\ = \dfrac{D}{3}[e^{-4} (2e^x x^3 -3x^2 -6x -6)]^4__2}}= 38.21 \ D$

Similarly;

$D\int\limits^4_2(2+ e^{-x}) dx = 1$

⇒ $D*(2x-e^{-x} ) |^4_2 = 1$

⇒ $D*4.117 = 1$

⇒ $D= \dfrac{1}{4.117}$

$\mu = E(x) = 2.991013 ; \\ \\ E(x^2) = 9.28103$

∴ $Var (x) = E(x^2) - E^2(x) \\ \\ = .3348711$

Now; $P(\bar \geq 2.3) = P( \bar x - 2.991013 \geq 2.3 - 2.991013) \\ \\ = P( \omega \geq .691013) \ \ \ \ \ \ \ \ \ \ (x = E(\bar x ) - \mu)$

Using Chebysher one sided inequality ; we have:

$P(\omega \geq -.691013) \geq \dfrac{(.691013)^2}{Var ( \omega) +(.691013)^2}$

So; $(\omega = \bar x - \mu)$

⇒ $E(\omega ) = 0 \\ \\ Var (\omega ) = \dfrac{Var (x_i)}{n}$

∴ $P(\omega \geq .691013) \geq \dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2}$

To determine n; such that ;

$\dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2} \geq 0.96 \\ \\ \\ (.691013)^2(1-.96) \geq \dfrac{-3348711*.96}{n}$

⇒ $n \geq \dfrac{.3348711*.96}{.04*(.691013)^2}$

$n \geq 16.83125$

Thus; we can conclude that; the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

5 0

2 years ago

What is the simplified form of -24m^5 n^4/ 8m^-7 n^-2

solong [7]

Answer:

-3·m^12·n^6

Step-by-step explanation:

We assume you intend ...

(-24·m^5·n^4)/(8·m^-7·n^-2)

= (-24/8)·m^(5-(-7))·n^(4-(-2))

= -3·m^12·n^6

_____

If you really intend what you have written, then it simplifies to ...

(-24·m^5·n^4/8)·m^-7·n^-2 . . . . . note that all factors involving m and n are in the numerator

= (-24/8)·m^(5-7)·n^(4-2) = -3n^2/m^2

8 0

2 years ago

A graph has a slope of -2 and a y-intercept of 4. Fill in the equation below using slope-intercept form. y= blank x+ blank

vfiekz [6]

Y=-2x+4 the first blank will be your slope and the second blank will be where your line crosses the y intercept

4 0

3 years ago

During a weekend, the manager of a mall gave away gift cards to every 80th person who visited the mall.

yuradex [85]

What is the question??

3 0

2 years ago

Evaluate g(x) = 1.873 -0.0034x +0.5 for x = 1 and x = 2.

AlexFokin [52]

Answer:

g(1) = 1.8696

g(2) = 1.8662

Step-by-step explanation:

Simply plug in the x values into the equation in a calc and you should get your answer.

6 0

3 years ago