Answer:
absolute max is 120 and absolute min is -8
Step-by-step explanation:
Find critical numbers
f'(x) = 3x^2 - 12x + 9 = 0
= 3(x^2 - 4x + 3) = 0
3(x-3)(x-1) = 0
(x-3) = 0 or (x-1)=0
x = 1,3
Test them!
x<1 Sign of f' on this interval is positive
1<x<3 Sign of f' on this interval is negative
x>3 Sign of f' on this interval is positive
f(x) changes from positive to negative at x = 1 which means there is a relative maximum here.
f(x) changes from negative to positive at x = 3 which means there is a relative minimum here.
Test the endpoints to find the absolute max and min.
f(-1) = -8
f(1) = 12
f(3) = 8
f(7) = 120
The absolute maximum value of f is 120 and the absolute minimum value of f is -8.
Answer:
Step-by-step explanation:
Given that the angle 
is located in Quadrant II; and
In Quadrant II, x is negative and y is positive.
To find 
, we first determine the opposite angle of .
This will be done using the Pythagoras theorem.
Therefore:
You would subtract the the amount painted from 500.
500-193=307
They have to paint 307 more.
Answer:50 %
Step-by-step explanation:
Given
There are 4 girls and 6 boys in a club
Probability of choosing 1 girl and 2 boys is
No of ways of choosing 1 girl and 2 boys
i.e. 
The formula for area of a triangle is 1/2 x base x height.
Let the height = x
Then the base (length) = 2x ( twice the height)
You know have 16 = 1/2 * 2x * x
Multiply both sides by 2 to remove the 1/2:
32 = 2x * x
Simplify the right side:
32 = 2x^2
Divide both sides by 2:
16 = x^2
Take the square root of both sides:
X = 4
The height is 4 units and the length is 8 Units
