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3 years ago

Question: find the value of x. CAN someone please help me please explain!!

Mathematics

1 answer:

ELEN [110]3 years ago

7 0

Step-by-step explanation:

Sum of interior angles of a polygon is given by (n-2)180°

where,n is the number of sides.

Since this polygon has 5sides,

sum of the interior angles = (5-2)180°=540°

x+150°+120°+75°+60°=540°

x°=540°-405° = 135°

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In the figure, lines a, b, and c are parallel and m∠4=68° . Drag and drop the correct angle measure for each angle. m∠1 = m∠2 =

melisa1 [442]

The complete question in the attached figure

we have that
m∠4=68°

we know that
m∠4 and m∠3 are supplementary angles
so
m∠3=180-m∠4----- m∠3=180-68------> m∠3=112°

m∠3 = m∠2 --------> by alternate interior angles
so
m∠2=112°

m∠1 = m∠4 --------> by alternate exterior angles
so
m∠1=68°

m∠5 = m∠4---------> by corresponding angles
so
m∠5=68°

the answers are
m∠1=68°
m∠2=112
m∠3=112°
m∠5=68°

3 0

2 years ago

Read 2 more answers

PLZS HELP THIS IS MY LAST QUESTION!!

Vikki [24]

Answer:

Step-by-step explanation:

According to figure, 

54° + 3x+36° = 180° [Linear pair]

=> 3x + 90 = 180

=> 3x = 180 - 90

=> 3x = 90

$= > x = \frac{90}{3}$

=> x = 30 (Ans)

4 0

2 years ago

Read 2 more answers

Find x when y = 5 in the literal equation 4x + 7y = 51

xeze [42]

The answer is... x=4

4(4) + 7(5) = 51

Hope ive helped!

8 0

3 years ago

Read 2 more answers

If 70% is £14 what is the full price

Veseljchak [2.6K]

70℅ = 14
100 = X

70X = 1400

X = 1400/70

X = 20

20 Euros is the full price

6 0

2 years ago

Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an

Natasha_Volkova [10]

Answer:

The volume of the solid is 243 $\sqrt{2} \ \pi$

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0 ≤ ρ² ≤ 81

0 ≤ ρ ≤ 9

The intersection that takes place in the sphere and the cone is:

$x^2 +y^2 ( \sqrt{x^2 +y^2 })^2 = 81$

$2(x^2 + y^2) =81$

$x^2 +y^2 = \dfrac{81}{2}$

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

$z = \sqrt{x^2+y^2}$

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; $\dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}$

Thus, volume: $V = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4} \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho ^2 \ sin \phi \ d\rho \ d \theta \ d \phi$

$V = \int \limits^{\pi/2}_{\pi/4} \ sin \phi \ d \phi \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho ^2 d\rho$

$V = \bigg [-cos \phi \bigg]^{\pi/2}_{\pi/4} \bigg [\theta \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3} \bigg ]^{9}_{0}$

$V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]$

V = 243 $\sqrt{2} \ \pi$

4 0

2 years ago