1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m².
a = 51 m, b = 37 m, c = 20 m
semiperimeter: p = (51+37+20):2 = 54 m
Area of triangle:

Rate: ₹ 3 per m².
Cost: ₹ 3•306 = ₹ 918
2. Find the area of the isosceles triangle whose perimeter is 11 cm and the base is 5 cm.
a = 5 cm
a+2b = 11 cm ⇒ 2b = 6 cm ⇒ b = 3 cm
p = 11:2 = 5.5

3. Find the area of the equilateral triangle whose each side is 8 cm.
a = b = c = 8 cm
p = (8•3):2 = 12 cm

4. The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3 : 2. Find the area of the triangle.
a = 2x
b = 3x
2x + 2•3x = 32 cm ⇒ 8x = 32 cm ⇒ x = 4 cm ⇒ a = 8 cm, b = 12 cm
p = 32:2 = 16 cm

Answer:
x3+3x2-x-3
Step-by-step explanation:
Hi there
The formula of the present value of annuity ordinary is
Pv=pmt [(1-(1+r/k)^(-kn))÷(r/k)]
So we need to find the monthly payment pmt
Pmt=pv÷[(1-(1+r/k)^(-kn))÷(r/k)]
Pv present value 205000
R interest rate 0.056
K compounded monthly 12
N time 30
PMT=205,000÷((1−(1+0.056÷12)^(
−12×30))÷(0.056÷12))
=1,176.86...answer
Hope it helps
Add 4 to boh sides
t/5+4-4=9+4
t/5+0=13
t/5=13
times 5/1 both sides
5t/5=5*13
1t=65
t=65