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3 years ago

Do the ratios 13 6 and 2 1 form a proportion?

Mathematics

1 answer:

Papessa [141]3 years ago

7 0

Answer:

No. The two ratios do NOT form a proportion.

Step-by-step explanation:

Cross multiply.

13/6 : 2/1

13(1) : 6(2)

13 ≠ 12

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What is the value of es026-1.jpg?

Kay [80]

Answer:

Value of $[(\frac{2}{3}) ^0]^{-3}$ is, 1

Step-by-step explanation:

To find the value of $[(\frac{2}{3})^0]^{-3}$

Using exponents power rule:

$(a^m)^n = a^{mn}$

then;

$(\frac{2}{3})^{0 \cdot (-3)}$

Simplify:

$(\frac{2}{3})^{0}$

By Zero exponent rule: Anything raised to the power 0 is 1. i.e,

$a^0 = 1$

then;

$(\frac{2}{3})^{0}$ = 1

Therefore, the value of $[(\frac{2}{3}) ^0]^{-3}$ is, 1

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3 years ago

What are the solutions to the equation 2x^2 + 9x =5

Maksim231197 [3]

Answer:

$\displaystyle -5 \ and \ \frac{1}{2}$

Step-by-step explanation:

$2x^2 + 9x =5$

we have to move 5 in the other side with a different sign, to get a 2 grade ecuation

$2x^2 + 9x -5= 0$

now we know

a=2

b=9

c=-5

we have to find delta

$\boxed{\Delta=b^2-4ac} \\\\ \Delta=9^2-4\cdot2\cdot(-5)\\ \Delta=81+40 \\ \Delta=121$

and now we have to use the formula to find the root square

$\displaystyle \boxed{ X_{1,2}=\frac{-b\pm\sqrt{\Delta} }{2a} }$

$\displaystyle X_1=\frac{-b-\sqrt{\Delta} }{2a} =\frac{-9-11}{2\cdot2}=\frac{-20}{4} =-5$

$\displaystyle X_2=\frac{-b+\sqrt{\Delta} }{2a} =\frac{-9+\sqrt{121} }{2\cdot4} =\frac{-9+11}{4} =\frac{2}{4} =\frac{1}{2}$

8 0

3 years ago

Read 2 more answers

PLZZ ANSWER ILL GIVE YOU BRAINLYIST

Monica [59]

Answer:

29.4 (B)

Step-by-step explanation:

<u>First, get rid of parentheses by multiplying.</u>

5(3 1/5 + 2 4/5) = 16 + 14 = 30.

Subtract 0.6

30 - 0.6 = 29.4

4 0

3 years ago

A true/false test has 8080 questions. Suppose a passing grade is 5252 or more correct answers. Test the claim that a student kn

Makovka662 [10]

<h2>Answer with explanation:</h2>

Let p be the proportion of the correct answers.

As per given , we have

$H_0: p=0.50$

$H_a: p>0.50$ , since the alternative hypothesis is right tailed , so the test is a one -tailed test.

If the student gets 52 answers correct out of 80.

i.e. the proportion of correct answers : $\dfrac{52}{80}=0.65$

Test statistic : $z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

$z=\dfrac{0.65-0.50}{\sqrt{\dfrac{0.50(0.50)}{80}}}\approx2.68$

P-value : $P(z>2.68)=0.0037$ [ by using p-value table for z (right-tailed)]

Since the p-value(0.0037) is less than the significance level (0.05), so we reject the null hypothesis.

Results : We have enough evidence to support the claim that a student knows more than half of the answers and is not just guessing.

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4 years ago

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sineoko [7]

Answer:

Option C is correct.........

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3 years ago