Wavelength = (speed) / (frequency)
The speeds of the two possible signals are equal, just like
all other forms of electromagnetic radiation.
Wavelength of 895 MHz = (3 x 10⁸ m/s) / (8.95 x 10⁸/s) = 0.335 m
Wavelength of 2560 MHz = (3 x 10⁸ m/s) / (2.56 x 10⁹/s) = 0.117 m
Answer:it causes the moving object to slow eventually stop
Explanation:
Answer:
I think is 3 I am not sure
Answer:
100 times
Explanation:
Question:
The cylinders of a hydraulic part are 15cm and 150cm in diameter. How many times will the force acting on the piston with the smaller diameter be multiplied?
Solution:
Smaller diameter = 15cm
Bigger diameter = 150cm
Using Pascal's principle
F/A = f/a
Pressure = Force/Area
Pressure on piston with bigger diameter = pressure on piston with smaller diameter
Let Pressure on piston with bigger diameter = P
P =F/A
pressure on piston with smaller diameter = p
p = f/a
F/A = f/a
F×a = f×A
F/f = A/a
Area = πr^2
F/f = [π×(150)^2]/ [π×(15)^2]
F/f = (150)^2/ (15)^2
F/f = 100
F = 100f
The force acting on the piston with the smaller diameter will be multiplied 100 times.
Answer:
a) m₁ = 1.41 kg
, b) m₂ = 2.65 kg
Explanation:
For this exercise we will use Newton's second law
Block 1
T - W₁ = m₁ a
Block 2
W₂ - T = m₂ a
We have selected the positive block 1 rising and block two lowering, as the pulley has no friction does not affect the movement
Let's use kinematics to look for acceleration
y = v₀ t + ½ a t²
As part of the rest the initial speed is zero
a = 2 y / t²
a = 2 6.00 / 2²
a = 3 m / s²
Let's replace in the equation of block 1
a) T = m₁ g + m₁ a
m₁ = T / (g + a)
m₁ = 18.0 / (9.8 + 3)
m₁ = 1.41 kg
b) we substitute in the equation of block 2
W₂ - T = m₂ a
m₂ g - m₂ a = T
m₂ = T / (g-a)
m₂ = 18.0 / (9.8 -3)
m₂ = 2.65 kg