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1 year ago

6

A 7.2 magnitude earthquake, with an epicenter in Northern Mexico, was felt over 100 miles away in Southern California because wa

ves generated by earthquakes
A
do not require a medium to propagate.

B
travel away from the epicenter with no interference.

C
carry energy through Earth's crust.

D
can be measured on a Richter scale.

1 answer:

ryzh [129]1 year ago

7 0

Answer:

B

because waves generated

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First, you will investigate purely vertical motion. The kinematics equation for vertical motion (ignoring air resistance) is giv

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Answer:

2.85 s .

Explanation:

y(t) = y(0) + v₀t + 1/2 gt²

y(t) is vertical displacement , y(0) is initial position , v₀ is initial velocity and t is time required to make vertical displacement and g is acceleration due to gravity.

Here y(0) is zero , v₀ = 14 m/s , g = 9.8 m s⁻² , y(t ) = 0 , as the pumpkin after time t comes back to its initial position, that is ground .

We shall take v₀ as negative as it is in upward direction and g as positive as it acts in downward direction

Put the values in the equation above,

0 = 0 - 14t + 1/2 x 9.8 t²

14 t = 1/2 x 9.8 t²

t = 28 / 9.8

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Slow moving vehicles must display ___________ emblem at the rear to warn of their low speed.

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A 25 MGD surface water drinking plant has four circular clarifiers (aka sedimentation basin), operated in parallel with each bas

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2 years ago

A coil is wrapped with 300 turns of wire on the perimeter of a circular frame (radius = 8.0 cm). Each turn has the same area, eq

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Answer:

Approximately 18 volts when the magnetic field strength increases from $\rm 20\; mT$ to $\rm 80\;mT$ at a constant rate.

Explanation:

By the Faraday's Law of Induction, the EMF $\epsilon$ that a changing magnetic flux induces in a coil is:

$\displaystyle \epsilon = N \cdot \frac{d\phi}{dt}$ ,

where

$N$ is the number of turns in the coil, and
$\displaystyle \frac{d\phi}{dt}$ is the rate of change in magnetic flux through this coil.

However, for a coil the magnetic flux $\phi$ is equal to

$\phi = B \cdot A\cdot \cos{\theta}$ ,

where

$B$ is the magnetic field strength at the coil, and
$A\cdot \cos{\theta}$ is the area of the coil perpendicular to the magnetic field.

For this coil, the magnetic field is perpendicular to coil, so $\theta = 0$ and $A\cdot \cos{\theta} = A$ . The area of this circular coil is equal to $\pi\cdot r^{2} = \pi\times 8.0\times 10^{-2}\approx \rm 0.0201062\; m^{2}$ .

$A\cdot \cos{\theta} = A$ doesn't change, so the rate of change in the magnetic flux $\phi$ through the coil depends only on the rate of change in the magnetic field strength $B$ . The size of the magnetic field at the instant that $B = \rm 50\; mT$ will not matter as long as the rate of change in $B$ is constant.

$\displaystyle \begin{aligned} \frac{d\phi}{dt} &= \frac{\Delta B}{\Delta t}\times A \\&= \rm \frac{80\times 10^{-3}\; T- 20\times 10^{-3}\; T}{20\times 10^{-3}\; s}\times 0.0201062\;m^{2}\\&= \rm 0.0603186\; T\cdot m^{2}\cdot s^{-1}\end{aligned}$ .

As a result,

$\displaystyle \epsilon = N \cdot \frac{d\phi}{dt} = \rm 300 \times 0.0603186\; T\cdot m^{2}\cdot s^{-1} \approx 18\; V$ .

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3 years ago

You are writing a short adventure story for your English class. In your story, two submarines on a secret mission need to arrive

levacccp [35]

Answer:

V = 31.17km/h

Explanation:

The average velocity is given by:

$V = \frac{d}{t}$ where d is the same distance traveled by the first submarine and t is the the same amout of time that it took.

d = 500km + 500km + 500km+ 500km = 2000km

t = t1 + t2 + t3 + t4

where

$t1 = \frac{d1}{V1} = \frac{500km}{20km/h}=25h$

$t2 = \frac{d2}{V2} = \frac{500km}{40km/h}=12.5h$

$t3 = \frac{d3}{V3} = \frac{500km}{30km/h}=16.67h$

$t4 = \frac{d4}{V4} = \frac{500km}{50km/h}=10h$

So, t = 25 + 12.5 + 16.67 + 10 = 64.17h

And finally:

$V = \frac{d}{t} = \frac{2000km}{64.17h}=31.17km/h$

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3 years ago