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Anni [7]
4 years ago
10

Cilindrii unei piese hidraulice au dimetrele 15cm și 150cm. De câte ori va fi multiplicată forța ce acționează asupra pistonului

cu diametrul mai mic?
Physics
1 answer:
Anuta_ua [19.1K]4 years ago
8 0

Answer:

100 times

Explanation:

Question:

The cylinders of a hydraulic part are 15cm and 150cm in diameter. How many times will the force acting on the piston with the smaller diameter be multiplied?

Solution:

Smaller diameter = 15cm

Bigger diameter = 150cm

Using Pascal's principle

F/A = f/a

Pressure = Force/Area

Pressure on piston with bigger diameter = pressure on piston with smaller diameter

Let Pressure on piston with bigger diameter = P

P =F/A

pressure on piston with smaller diameter = p

p = f/a

F/A = f/a

F×a = f×A

F/f = A/a

Area = πr^2

F/f = [π×(150)^2]/ [π×(15)^2]

F/f = (150)^2/ (15)^2

F/f = 100

F = 100f

The force acting on the piston with the smaller diameter will be multiplied 100 times.

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Answer:

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7 0
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A force of 20 N produces an acceleration of 10 m/s² in mass m1 and an acceleration of 5 m/s² in
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Explanation:

F = 20N m= m1 a=10m/s²

m=m2 a=5m/s²

F = ma

<u>for the first one</u><u>:</u><u> </u>

f=m1 × a

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20=10m1

m1=20/10

m1=2

<u>for</u><u> </u><u>the</u><u> </u><u>second</u><u> </u><u>one</u><u> </u><u>:</u>

f=m2×a

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F=20(from the question above )

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8 0
4 years ago
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Answer:

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Explanation:

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4 0
3 years ago
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Answer:

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