5. A rectangle ABCD has vertices A(-2, 3), B(3, 3), C(3, -5). Find the coordinates of D.

Mathematics

1 answer:

marta [7]1 year ago

3 0

Answer: Area is 40, Cord is (-2,-5)

Step-by-step explanation:

You might be interested in

PLEASE PLEASE PLEASE The graph of g(x), shown below, resembles the graph of f(x) = x^4-x^2 but it has been changed somewhat. Whi

galina1969 [7]

<h2>Answer: D</h2>

Step-by-step explanation:

5 0

3 years ago

What is the rule for Aaliyah’s machine? Try to write the rule as an equation.

Eva8 [605]

Answer:

f(x) = 2x +1

Step-by-step explanation:

Apparently the ordered pairs are ...

(x, f(x)) = (1, 3), (2, 5), (3, 7), (4, 9)

We note that as x increases by 1, the value of f(x) increases by 2. The difference between f(x) and 2x is 3-2·1 = 1, so we have ...

f(x) -2x = 1

f(x) = 2x +1 . . . . . . add 2x

4 0

4 years ago

James age is 3 years less than twice Tori's age the sum of their ages is 30 find their ages

blagie [28]

Error// Error// Error// Error// Error// Error//

7 0

3 years ago

There are 3 red and 8 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probabilit

Kaylis [27]

So, the total number of balls is 11. We want to pick 2 red balls and 1 green ball. WLOG (since order doesnt matter here), we can say he picks red, green, red. That means on his first pick, he has a $\frac{3}{11}$ chance of picking the red ball, and he places it back in the bag. The probability of picking a green ball is $\frac{8}{11}$ , and then he places the ball back in the bag. The probability of picking the last red ball is the same as the last red ball example, and we simply multiply the probabilities together as per the multiplication rule to get:

$\frac{3}{11}\frac{3}{11}\frac{8}{11}=\frac{3*3*8}{11^3}=\frac{72}{1331}$

Now, without replacement the order does matter. He picks a red ball, a red ball then a green ball. The probability of picking the first red ball is $\frac{2}{11}$ , and the probability of picking the second red ball is $\frac{1}{10}$ and the probability of picking the green ball is $\frac{1}{9}$ . We want to multiply thm again, as per the multiplication rule like the last problem.