Answer:
(A) $157.25
(B) $3,857.25
Step-by-step explanation:
The given values are:
Principle (P)
= $3700
Time (T)
= 6 months i.e., 1/2 years
Rate (R)
= 8.5%
(A)
As we know,
Simple Interest,
⇒ 
On putting the values, we get
⇒ 
⇒ 
⇒
($) (he paid for the use of money)
(B)
Amount he paid to the bank will be:
⇒ 
⇒ 
⇒
($)
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Answer:
yes a
Step-by-step explanation:
Answer:
0.865
Step-by-step explanation:
To solve for the probability we would be using the formula:
F(x) = 1 - e^−λx
Therefore, P(x > 2000) = F(x) = 1 - e^−λx
Mean = 1000 hours
λ = 1/mean = 1/1000 hours
x= 2000 hours
F(x) = 1 - e^−(1/1000)2000
F(x) = 1 - e^−2
= 0.8646647168
Therefore, the probability the the circuit will last at least 2000 hours = 0.865