Answer:
Hope this helps :)
Step-by-step explanation:
15
(3^5)÷(3^5)
Simplify 3^5
243÷243
1
(3^5)÷(3^5)
3^5/3^5=3^5-5
3^5-5
3^5-5= 1
1
Formula: x^a/x^b=x^a-b
16
2^10/2^10
Cancel out 2^10
1
2^10/2^10
2^10/2^10=2^10-10
2^10-10
2^10-10=1
1
Formula: x^a/x^b=x^a-b
17
x^7/x^7x≠0
x≠0
18
(4x+2y)5÷(4x+2y)^5(4x+2y) ≠ 0
5/(4x+2y)^3 ≠ 0
5 ≠ 0
≠ =-y/2
19
No solution
20
p^4/p^4p ≠ 0
p≠ 0
no solution
2.8 is the correct answer :)
56 -13-14-3= 26 boxes of cookies left to sell
Answer:
57.49% probability that a randomly selected individual has an IQ between 81 and 109
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Find the probability that a randomly selected individual has an IQ between 81 and 109
This is the pvalue of Z when X = 109 subtracted by the pvalue of Z when X = 81. So
X = 109



has a pvalue of 0.67
X = 81



has a pvalue of 0.0951
0.67 - 0.0951 = 0.5749
57.49% probability that a randomly selected individual has an IQ between 81 and 109