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Veseljchak [2.6K]

4 years ago

9

The base of the prism in the diagram is rectangular, but the edges that are not parallel to the base titled. What is the volume

of the prism?

1 answer:

joja [24]4 years ago

4 0

The answer is
the volume of the prism is 648\ cm^{3}

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I need<br> 7<br> 50<br> of fuel in %

docker41 [41]

Answer:

14%

Step-by-step explanation:

4 0

3 years ago

a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample s

Alex

Answer:

95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

Step-by-step explanation:

We are given that a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample standard deviation of the number of tissues per box is 97.

Firstly, the pivotal quantity for 95% confidence interval for the population variance is given by;

P.Q. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, $s^{2}$ = sample variance = $97^{2}$ = 9409

n = sample of boxes = 15

$\sigma^{2}$ = population variance

<em>Here for constructing 95% confidence interval we have used chi-square test statistics.</em>

So, 95% confidence interval for the population variance, $\sigma^{2}$ is ;

P(5.629 < $\chi^{2}__1_4$ < 26.12) = 0.95 {As the critical value of chi-square at 14

degree of freedom are 5.629 & 26.12}

P(5.629 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 26.12) = 0.95

P( $\frac{5.629 }{(n-1)s^{2} }$ < $\frac{1}{\sigma^{2} }$ < $\frac{26.12 }{(n-1)s^{2} }$ ) = 0.95

P( $\frac{(n-1)s^{2} }{26.12 }$ < $\sigma^{2}$ < $\frac{(n-1)s^{2} }{5.629 }$ ) = 0.95

<u><em>95% confidence interval for</em></u> $\sigma^{2}$ = [ $\frac{(n-1)s^{2} }{26.12 }$ , $\frac{(n-1)s^{2} }{5.629 }$ ]

= [ $\frac{14 \times 9409 }{26.12 }$ , $\frac{14 \times 9409 }{5.629 }$ ]

= [5043.11 , 23401.31]

Therefore, 95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

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3 years ago

QUICK! The radius of a cylindrical construction pipe is 2 ft. If the pipe is 16 ft long, what is its volume?

Alika [10]

Answer:

V=201.06 ft²

Step-by-step explanation:

V= $\pi$ r²h

V= $\pi$ 2²16

V=64 $\pi$

V=201.06

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3 years ago

Read 2 more answers

11 less than twice a number is 5

igomit [66]

Answer:

2x - 11 = 5

Step-by-step explanation:

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4 years ago

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4 years ago