Is y=y+8 even, odd, or neither

Mathematics

1 answer:

SIZIF [17.4K]1 year ago

3 0

The expression y = y + 8 does neither represent an odd number nor an even number.

<h3>Does represent a given equation an even or odd number or neither?</h3>

In this problem we must check if a given algebraic equation represents an even number or an odd number or neither by using algebraic means. Even numbers are integers, whose last digit is 0, 2, 4, 6 or 8, whereas odd numbers are integers, whose last digit is 1, 3, 5, 7 or 9. Now we proceed to check the expression:

y = y + 8 Given

y + (- y) = 8 Compatibility with addition / Existence of additive inverse / Modulative property

0 = 8 Existence of additive inverse / Modulative property / Result

The expression y = y + 8 does neither represent an odd number nor an even number.

To learn more on even numbers: brainly.com/question/2289438

#SPJ1

You might be interested in

A 2-column table with 8 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2, 3, 4. The

mrs_skeptik [129]

Answer:

Option B.

Step-by-step explanation:

The given table of values is

x f(x)

-3 -2

-2 0

-1 2

0 2

1 0

2 -8

3 -10

4 -20

We need to find the interval for which the function f(x) is positive.

From the given table it is clear that the value of function f(x) is negative before -2 and after 1.

The function positive between x=-2 and x=1. So, we can conclude that the function f(x) is positive for the interval (-2,1).

Therefore, he correct option is B.

5 0

3 years ago

Read 2 more answers

In the 1980’s, a clinical trial was conducted to determine if taking an aspirin daily reduced the incidence of heart attacks. Of

zubka84 [21]

There is enough evidence to conclude that taking aspirin cannot reduces the chance of cancer.

Given sample size of patients take aspirin 11037, sample size of patients who have assigned placebo group be 11034. 104 doctors who take aspirin had a heart attack, 189 doctors had placebo had heart attacks.

First we have to form hypothesis.

$H_{0} :p{1} -p_{2} =0$