Question

What is the solution to the following system of equations?

Answer 1

Hi there!

x + 2y = 2
x - 2y = -2

We need to solve x + 2y = 2 for y
x = 2y +2
Now substitute -2y + 2 for x in x - 2y =-2
x -2y = -2
-2y + 2 - 2y= -2
-4y + 2 = -2
-4y = -2 - 2
-4y = -4
y = -4/-4
y= 1

We gonna use the value of y to find x
We gonna find x by substitute 1 for y in x = -2y + 2
x = -2y + 2
x = -2(1)+2
x= -2 + 2
x = 0

Hence,
 x = 0 and y = 1

So the correct option is (0,1)

I hope I helped!