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kap26 [50]
4 years ago
10

Elevii clasei a IV-a au fost la patinoar. Stiind ca numarul baietilor reprezinta jumatate plus 3 din numarul copiilor si ca numa

rul fetelor este 10, afla cati copii au fost la patinoar.
Mathematics
1 answer:
earnstyle [38]4 years ago
3 0

Step-by-step explanation:

Să presupunem că x să fie numărul de copii

De\:asemenea

să fiu fetele

f = 10

și

b\:=\:\frac{x}{2}\:+\:3

f\:+\:b\:=\:x

substituirea valorilor

10\:+\:\frac{x}{2}\:+\:3\:=\:x

20\:+\:x\:+\:6\:=\:2x

x\:=\:26     copii au fost la patinoar

b=\frac{26}{2}+\:3

b\:=\:16\:baieti

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PLS HELP FIRST CORRECT ANSWER GETS BRAINLEIST​
Wewaii [24]

Answer: 168cm^2

Step-by-step explanation:

lets split this into two shapes:

a rectangle and a triangle

Formulas:

rect: b * h

Tri: (b*h)/2

Solve:

12 * 10 = 120

(12*8)/2 = 48

120 + 48 =

168cm^2

4 0
2 years ago
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Psychologist Michael Cunningham conducted a survey of university women to see whether, upon graduation, they would prefer to mar
bagirrra123 [75]

Answer:

A.The probability that exactly six of Nate's dates are women who prefer surgeons is 0.183.

B. The probability that at least 10 of Nate's dates are women who prefer surgeons is 0.0713.

C. The expected value of X is 6.75, and the standard deviation of X is 2.17.

Step-by-step explanation:

The appropiate distribution to us in this model is the binomial distribution, as there is a sample size of n=25 "trials" with probability p=0.25 of success.

With these parameters, the probability that exactly k dates are women who prefer surgeons can be calculated as:

P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{25}{k} 0.25^{k} 0.75^{25-k}\\\\\\

A. P(x=6)

P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.00024*0.00423=0.183\\\\\\

B. P(x≥10)

P(x\geq10)=1-P(x

P(x=0) = \dbinom{25}{0} p^{0}(1-p)^{25}=1*1*0.0008=0.0008\\\\\\P(x=1) = \dbinom{25}{1} p^{1}(1-p)^{24}=25*0.25*0.001=0.0063\\\\\\P(x=2) = \dbinom{25}{2} p^{2}(1-p)^{23}=300*0.0625*0.0013=0.0251\\\\\\P(x=3) = \dbinom{25}{3} p^{3}(1-p)^{22}=2300*0.0156*0.0018=0.0641\\\\\\P(x=4) = \dbinom{25}{4} p^{4}(1-p)^{21}=12650*0.0039*0.0024=0.1175\\\\\\P(x=5) = \dbinom{25}{5} p^{5}(1-p)^{20}=53130*0.001*0.0032=0.1645\\\\\\P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.0002*0.0042=0.1828\\\\\\

P(x=7) = \dbinom{25}{7} p^{7}(1-p)^{18}=480700*0.000061*0.005638=0.1654\\\\\\P(x=8) = \dbinom{25}{8} p^{8}(1-p)^{17}=1081575*0.000015*0.007517=0.1241\\\\\\P(x=9) = \dbinom{25}{9} p^{9}(1-p)^{16}=2042975*0.000004*0.010023=0.0781\\\\\\

P(x\geq10)=1-(0.0008+0.0063+0.0251+0.0641+0.1175+0.1645+0.1828+0.1654+0.1241+0.0781)\\\\P(x\geq10)=1-0.9287=0.0713

C. The expected value (mean) and standard deviation of this binomial distribution can be calculated as:

E(x)=\mu=n\cdot p=25\cdot 0.25=6.25\\\\\sigma=\sqrt{np(1-p)}=\sqrt{25\cdot 0.25\cdot 0.75}=\sqrt{4.69}\approx2.17

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3 years ago
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You did not include the problem therefore i cannot help you with this but if you could message me the problem i’d be happy too
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1) From Kim

2) From Daniel


Let:

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y be the cost of rolls of shiny wrapping paper


Kim:

7x + 8y = 140

Daniel:

14x + 7y = 154


<u>Using elimination method:</u>

(7x + 8y = 140) * -2  (Multiplying the equation by -2)

-14x - 16y = -280


-14x  -16y = -280

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4 years ago
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30 - 300
3 tens - 30
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3 years ago
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