Question

3. The perimeter of a rectangular playing field is 504 yards. The area of the

Answer 1

The perimeter is twice the sum of the length and the width:

$P = 2(w+l)$

The area is the product of the dimensions:

$A = wl$

So, the system is

$\begin{cases}w+l=504\\w\cdot l=14276\end{cases}$