Question

Angel left his house at time zero and drove for 3 minutes to the store, at a speed of 6

Answer 1

The motion to the store in 3 minutes, then the bank which is 2 blocks from the store, and returning home at 10 blocks/minute gives attached distance/time graph.

How can the graph of distance traveled to time taken be obtained?

The given parameters are;

• Time at which Angel left his house = 0 min

• Duration of the drive to the store, t1 = 3 min.

• Driving speed to the store, v1 = 6 blocks/min

• Duration of the stop at the store, t2 = 4 min

• Driving speed from store to bank, v2 = 1 block/min

• Distance from store to the bank = 2 blocks

• Time spent at the bank, t3 = 3 minutes

• Driving speed while returning back home = 10 blocks/min

Graph required; Distance/time graph

Solution;

$Speed = \mathbf{\frac{Distance}{Time}}$

Therefore;

Distance = Speed × Time

Distance, d1 between the house and the store is therefore;

d1 = v1 × t1

Therefore;

d1 = 6 blocks/min × 3 min = 18 blocks

The distance of the bank from the house, d4, from the coordinate, (12, 20), is therefore;

d4 = 20 blocks

$Time = \frac{Distance}{Speed}$

The time it takes to return home, t4 is therefore;

$t_4 = \frac{20 \: blocks}{10 \: blocks/min} = 2 \: minutes$

Which gives the point at which Angel gets home as (14, 0)

The coordinates of points on the graph of distance, d, versus time, t, where distance is on the vertical axis, are therefore;

(0, 0), (3, 18) (7, 18), (9, 20), (12, 20), (14, 0)

The graph of the above points created using Sheets is attached.

Learn more about plotting a line graph here:

brainly.com/question/3237998

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