What expression is equivalent to 5(3-2n)+12n ?<br> Break it down please

A machine, when working properly, produces 5% or less defective items. Whenever the machine produces significantly greater than

vovikov84 [41]

Answer:

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

Step-by-step explanation:

A machine, when working properly, produces 5% or less defective items.

This means that the null hypothesis is:

$H_0: p \leq 0.05$

Test if the percentage of defective items produced by this machine is greater than 5%.

This means that the alternate hypothesis is:

$H_a: p > 0.05$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.05 is tested at the null hypothesis:

This means that $\mu = 0.05, \sigma = \sqrt{0.05*0.95}$

A random sample of 300 items taken from the production line contained 27 defective items.

This means that $n = 300, X = \frac{27}{300} = 0.09$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.09 - 0.05}{\frac{\sqrt{0.05*0.95}}{\sqrt{300}}}$

$z = 3.18$

Pvalue of the test:

Testing if the mean is greater than a value, which means that the pvalue of the test is 1 subtracted by the pvalue of Z = 3.18, which is the probability of a finding a sample proportion of 0.09 or higher.

Looking at the Z-table, Z = 3.18 has a pvalue of 0.9993

1 - 0.9993 = 0.0007

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

5 0

3 years ago

Plsss help me !!!!

Yuri [45]

Answer:

The enrollment after 5 years is 10,724

Step-by-step explanation:

Generally, we can have the depreciation formula written as follows;

A = P(1 - r)^t

A is the number of enrollment in after a certain number of years t

P is the initial population which is 13,500

r is the rate of depreciation which is 4.5% = 4.5/100 = 0.045

t = 5 years

Substituting these values, we have it that;

A = 13,500(1-0.045)^5

A = 10,723.84

4 0

3 years ago

A bottle is filled with saline solution for eyes, is the bottle more likely to hold 15 milliliters of solution or 1 liter of sol

Gnesinka [82]

The bottle is more likely to hold 15 milliliters

hope this helped

3 0

3 years ago

The lateral area of a cube is 36 Square inches. How long is each edge?

mr_godi [17]

Answer:

D

Step-by-step explanation:

4 0

3 years ago

What is the area of a regular pentagon with 7 inch sides and an apothem of 3.9 inches?

Marrrta [24]

A(n)=(ns^2)/(4tan(180/n)) in this case:

a=(5*49)/(4tan36)

a=84.3in^2

8 0

3 years ago

What expression is equivalent to 5(3-2n)+12n ? Break it down please