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2 years ago

For each pair, which has higher potential energy?

Chemistry

1 answer:

zaharov [31]2 years ago

3 0

(a) The fuel in your car or the gaseous products in its exhaust

Fuel in our car (gasoline and oxygen) has more chemical potential energy than the exhaust gases they form.

Potential energy: It is the energy associated with forces of attraction and repulsion between objects which leads to the formation of energy.

The change of the fuel into the gaseous products is the chemical change of the substances.

A chemical change is a change in which one chemical substance is transformed into one or more than one substance.

It is always an irreversible reaction.

Example: Rusting of iron.

To know more about Chemical change, refer to this link:

brainly.com/question/23693316

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How many grams of CaCl2 are in 250 mL of 2.0 M CaCl2?

Tom [10]

The answer is:  " 56 g CaCl₂ " .
__________________________________________________________

Explanation:
__________________________________________________________
2.0 M CaCl₂ = 2.0 mol CaCl₂ / L ;

Since: "M" = "Molarity" (measurement of concentration);

= moles of solute per L {"Liter"} of solution.
__________________________________________________________
Note the exact conversion: 1000 mL = 1 L .

Given: 250 mL ;

250 mL = ? L ? ;

250 mL * (1 L / 1000 L) = (250/1000) L = 0.25 L .
___________________________________________________________

(2.0 mol CaCl₂ / L ) * (0.25L) = (2.0) * (0.25) mol  = 0.50 mol CaCl₂ ;

We have: 0.50 mol CaCl₂ ; Convert to "g" (grams):

→ 0.50 mol CaCl₂ .
___________________________________________________________
1 mol CaCl₂ = ? g ?

From the Periodic Table of Elements:

1 mol Ca = 40.08 g

1 mol Cl = <span>35.45 g .
</span>
There are 2 atoms of Cl in " CaCl₂ " ;

→ Note the subscript, "2", in the " Cl₂ " ;
__________________________________________________________
So, to calculate the molar mass of "CaCl₂" :

40.08 g + 2(35.45 g) =

40.08 g + 70.90 g = 110.98 g ; round to 4 significant figures;

→ round to 111 g/mol .
__________________________________________________________
So:

→ 0.50 mol CaCl₂ = ? g CaCl₂ ? ;

→ 0.50 mol CaCl₂ * (111 g CaCl₂ / mol CaCl₂) ;

= (0.50) * (111 g) CaCl₂ ;

= 55.5 g CaCl₂ ;

  → round to 2 significant figures;

  → 56 g CaCl₂ .
___________________________________________________________
The answer is: " 56 g CaCl₂ " .
___________________________________________________________

6 0

3 years ago

Read 2 more answers

Consider the following reaction:

True [87]

Answer:

Explanation:

I'm assume that 3 Br2 + 6 OH¹-5 Br¹ + BrO3¹ + 3 H₂O is meant to read:

3 Br2 + 6 OH^-1 = 5 Br^-¹ + BrO3^-¹ + 3 H₂O

The balanced equation tells us that 3 moles of Br2 will react with 6 moles of OH^-1 to produce 5 moles of Br^-1.

The first step is to determine whether the Br2 or OH^-1 are limiting reagents. That is, is there enough of each to complete the reaction, with none left over.

We need 3 moles of Br2 for every 6 moles of OH^-1, a molar ratio of 1/2 (Br2/OH).

We are given 4.68 moles of Br2 and 8.12 moles of OH^-1. That is a ratio of 4.68/8.12 or 0.5764. This is higher than the ratio of 1/2 or 0.5 that is required. That means we have more than enough Br2. The limiting reagent is the OH^-1. Once it is consumed, the reaction stops and we are left with some unreacted Br2.

So we need the molar ratio of the OH^-1 to the Br from the balanced equation: We see that 6 moles of OH^-1 are required to produce 5 moles of Br, a 6/5 molar ratio.

Therefore, we may assume all 8.12 moles of the limiting reagent, OH^-1, will be consumed to produce *6/5) that amount of Br.

(8.12 moles OH^-1)*((6 moles Br)/(5 moles OH^-1)) = 9.75 moles of Br.

For curiosity's sake, we can determine the amount of unreacted Br2. 8.12 moles of OH^-1 would require (8.12 moles OH)*(1/2) = 4.06 moles of Br2.

4.68 moles starting Br2

4.06 moles consumed

0.62 moles remaining Br2

7 0

2 years ago

Consider a solution that contains both C6H5NH2 and C6H5NH3+. Calculate the ratio [C6H5NH2]/[C6H5NH3+] if the solution has the fo

Tcecarenko [31]

The question has incomplete information. The pH values are not discriminated. Let's do, as an example, to pH = 4.69.

Answer:

For pH = 4.69, [C₆H₅NH₂]/[C₆H₅NH₃⁺] = 0.708

Explanation:

C₆H₅NH₂ is a base, and, when in aqueous solution, forms a conjugate acid, which is C₆H₅NH₃⁺. The equilibrium between these two species makes a buffer, a solution that prevents the change in pH by the addition of base or acid.

The pH of a buffer can be calculated by the equation of Handerson-Halsebach:

pH = pKa + log[conjugate base]/[acid]

Where pKa = -logKa, and Ka is the equilibrium constant of the acid. For the base, the equilibrium constant, Kb, is equal to 7x10⁻¹⁰, and

Ka*Kb = Kw

Where Kw is the equilibrium constant for water 1.00x10⁻¹⁴, so Ka for the conjugate acid is:

Ka = 1.00x10⁻¹⁴/7.00x10⁻¹⁰

Ka = 1.43x10⁻⁵

pKa = 4.84

pH = 4.84 + log [C₆H₅NH₂]/[C₆H₅NH₃⁺] (By this step, the pH values given by the question must be substituted)

4.69 = 4.84 + log[C₆H₅NH₂]/[C₆H₅NH₃⁺]

log[C₆H₅NH₂]/[C₆H₅NH₃⁺] = - 0.15

[C₆H₅NH₂]/[C₆H₅NH₃⁺] = $10^{-0.15}$

[C₆H₅NH₂]/[C₆H₅NH₃⁺] = 0.708

8 0

3 years ago

Discuss the manufacturer of HNO3 and H2SO4 by Harbers process

tino4ka555 [31]

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6 0

3 years ago

If the Kelvin temperature of a gas is doubled, the volume of the gas will increase by ____

liraira [26]

If the Kelvin temperature of a gas is doubled, the volume of the gas will increase by two. It follows Charles law where in for a mixed gas of mass, the volume is directly proportional to the temperature at constant pressure.

3 0

3 years ago