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Ksenya-84 [330]
3 years ago
12

Fog is composed of water droplets in air. Which term describes fog? A. solution B. colloid C. suspention D. solvent

Chemistry
2 answers:
Temka [501]3 years ago
8 0

Answer:

colloid

Explanation:

I got it right on egd

taurus [48]3 years ago
6 0

Answer:

colloid

Explanation:

Colloid is a type of fog

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Answer:

During a total lunar eclipse, the Earth lies directly between the sun and the moon, causing the Earth to cast its shadow on the moon.

Explanation:

4 0
3 years ago
Design a synthesis of 2-bromo-1-chloro-4-nitrobenzene from benzene or any mono-substituted benzene. Part 1 out of 6 choose the b
Oxana [17]

2-bromo-1-chloro-4-nitrobenzene  is being synthesized in following sequence:

Step 1: Chlorination of Benzene:

                                                     This is Halogenation reaction of benzene. In this step benzene is reacted with Chlorine gas in the presence of lewis acid (i.e. FeCl₃). This results in the formation of Chlorobenzene as shown in red step below.

Step 2: Nitration of Chlorobenzene:

                                                          The chlorine atom on benzene has a ortho para directing effect. Therefore, the nitration of chlorobenzene will yield para nitro chlorobenzene as shown in blue step below.

Step 3: Bromination of 1-chloro-4-nitrobenzene:

                                                                               In this step bromination is done by reacting bromine in the presence of lewis acid. The chlorine being ortho para directing in nature and nitro group being meta directing in nature will direct the incoming Br⁺ (electrophile) to the desired location. Hence, 2-bromo-1-chloro-4-nitrobenzene is synthesized in good yield.

6 0
3 years ago
Geologic plates can?....
Angelina_Jolie [31]
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5 0
3 years ago
Read 2 more answers
What is the name of the ionic compound, NaOH
Arisa [49]
SODIUM HYDROXIDE

IUPAC ID


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7 0
3 years ago
1. How many grams of B are present in 3.35 grams of boron tribromide ?
Andre45 [30]

Answer:

The answer to your question is:

Explanation:

1. How many grams of B are present in 3.35 grams of boron tribromide ?

________ grams B.

MW BBr₃ = 251 g

                            251 g of BBr₃ ----------------------  11 g of B

                             3.35 g          -----------------------    x

                           x = (3.35 x 11) / 251 = 0.147 g of B

2. How many grams of boron tribromide contain 4.69 grams of Br ?

________grams boron tribromide.

MW BBr₃ = 251g

                             251g of BBr₃ -----------------   80 g of Br

                                   x               ----------------- 4.69 g

                           x = (4.69 x 251)/ 80 = 14.71 g of BBr₃

3. How many grams of N are present in 4.11 grams of nitrogen trifluoride ?

________grams N.

MW NF₃ = 71 g

                               71 g of NF₃    -----------------   14 g of N

                               4.11 g              ----------------     x

                               x = (4.11 x 14) / 71 = 0.81 g of N

4. How many grams of nitrogen trifluoride contain 3.07 grams of F ?

________grams nitrogen trifluoride.

MW NF₃ = 71

                                71 g of NF₃ ---------------------   19 g of F

                                  x               ---------------------   3.07 g

                                 x = (3.07 x 71) / 19 = 11.5 g of NF₃

5.How many grams of Co3+ are present in 1.16 grams of cobalt(III) iodide?

________grams Co3+.

MW CoI₃ = 440 g

                             440 g of CoI₃ ------------------  59 g of Co

                              1.16 g             ------------------   x

                              x = (1.16 x 59) / 440 = 0.16 g of Co

6. How many grams of cobalt(III) iodide contain 2.28 grams of Co3+?

________grams cobalt(III) iodide.

MW CoI₃ = 440 g

                             440 g of CoI₃ ------------------  59 g of Co

                               x                   -----------------   2.28 g of Co⁺³

                              x = (2.28 x 440) / 59

                              x = 17 g of CoI₃

5 0
3 years ago
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